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A038712
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Let k be the exponent of highest power of 2 dividing n (A007814); a(n) = 2^(k+1)-1.
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65
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1, 3, 1, 7, 1, 3, 1, 15, 1, 3, 1, 7, 1, 3, 1, 31, 1, 3, 1, 7, 1, 3, 1, 15, 1, 3, 1, 7, 1, 3, 1, 63, 1, 3, 1, 7, 1, 3, 1, 15, 1, 3, 1, 7, 1, 3, 1, 31, 1, 3, 1, 7, 1, 3, 1, 15, 1, 3, 1, 7, 1, 3, 1, 127, 1, 3, 1, 7, 1, 3, 1, 15, 1, 3, 1, 7, 1, 3, 1, 31, 1, 3, 1, 7, 1, 3, 1, 15, 1, 3, 1, 7, 1, 3, 1, 63, 1, 3
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OFFSET
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1,2
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COMMENTS
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n XOR n-1, i.e., nim-sum of a pair of consecutive numbers.
Denominator of quotient sigma(2*n)/sigma(n). - Labos Elemer, Nov 04 2003
a(n) = the Towers of Hanoi disc moved at the n-th move, using standard moves with discs labeled (1, 3, 7, 15, ...) starting from top (smallest = 1). - Gary W. Adamson, Oct 26 2009
In the binary expansion of n, delete everything left of the rightmost 1 bit, and set all bits to the right of it. - Ralf Stephan, Aug 22 2013
Every finite sequence of positive integers summing to n may be termwise dominated by a subsequence of the first n values in this sequence [see Bannister et al., 2013]. - David Eppstein, Aug 31 2013
Sum of powers of 2 dividing n. - Omar E. Pol, Aug 18 2019
Given the binary expansion of (n-1) as {b[k-1], b[k-2], ..., b[2], b[1], b[0]}, then the binary expansion of a(n) is {bitand(b[k-1], b[k-2], ..., b[2], b[1], b[0]), bitand(b[k-2], ..., b[2], b[1], b[0]), ..., bitand(b[2], b[1], b[0]), bitand(b[1], b[0]), b[0], 1}. Recursively stated - 0th bit (L.S.B) of a(n), a(n)[0] = 1, a(n)[i] = bitand(a(n)[i-1], (n-1)[i-1]), where n[i] = i-th bit in the binary expansion of n. - Chinmaya Dash, Jun 27 2020
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LINKS
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FORMULA
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Sum_{n>0} a(n)*x^n/(1+x^n) = Sum_{n>0} x^n/(1-x^n). Inverse Moebius transform of A048298. - Vladeta Jovovic, Jan 02 2003
G.f.: Sum_{k>=0} 2^k*x^2^k/(1 - x^2^k).
a(2*n+1) = 1, a(2*n) = 2*a(n)+1. (End)
Dirichlet g.f.: zeta(s)/(1 - 2^(1-s)). - R. J. Mathar, Mar 10 2011
L.g.f.: -log(Product_{k>=0} (1 - x^(2^k))) = Sum_{n>=1} a(n)*x^n/n. - Ilya Gutkovskiy, Mar 15 2018
a(n) = sigma(n)/(sigma(2*n) - 2*sigma(n)) = 3*sigma(n)/(sigma(4*n) - 4*sigma(n)) = 7*sigma(n)/(sigma(8*n) - 8*sigma(n)), where sigma(n) = A000203(n). - Peter Bala, Jun 10 2022
Sum_{k=1..n} a(k) ~ n*log_2(n) + (1/2 + (gamma - 1)/log(2))*n, where gamma is Euler's constant (A001620). - Amiram Eldar, Nov 24 2022
a(n) = Sum_{d divides n} m(d)*phi(d), where m(n) = Sum_{d divides n} (-1)^(d+1)* mobius(d). - Peter Bala, Jan 23 2024
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EXAMPLE
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a(6) = 3 because 110 XOR 101 = 11 base 2 = 3.
Illustration of initial terms:
a(n) is also the area of the n-th region of an infinite diagram of compositions (ordered partitions) of the positive integers, where the length of the n-th horizontal line segment is equal to A001511(n) and the length of the n-th vertical line segment is equal to A006519(n), as shown below (first eight regions):
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n a(n) Diagram
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. _ _ _ _
1 1 |_| | | |
2 3 |_ _| | |
3 1 |_| | |
4 7 |_ _ _| |
5 1 |_| | |
6 3 |_ _| |
7 1 |_| |
8 15 |_ _ _ _|
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The above diagram represents the eight compositions of 4: [1,1,1,1],[2,1,1],[1,2,1],[3,1],[1,1,2],[2,2],[1,3],[4].
(End)
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MAPLE
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nmax:=98: for p from 0 to ceil(simplify(log[2](nmax))) do for n from 1 to ceil(nmax/(p+2)) do a((2*n-1)*2^p) := 2^(p+1)-1 od: od: seq(a(n), n=1..nmax); # Johannes W. Meijer, Feb 01 2013
# second Maple program:
a:= n-> Bits[Xor](n, n-1):
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MATHEMATICA
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Table[Denominator[DivisorSigma[1, 2*n]/DivisorSigma[1, n]], {n, 1, 128}]
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PROG
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(C) int a(int n) { return n ^ (n-1); } // Russ Cox, May 15 2007
(Haskell)
import Data.Bits (xor)
(Python)
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CROSSREFS
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A038713 translated from binary, diagonals of A003987 on either side of main diagonal.
a(n)-1 is exponent of 2 in A089893(n).
This is Guy Steele's sequence GS(6, 2) (see A135416).
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KEYWORD
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easy,nonn,mult
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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