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A259374 Palindromic numbers in bases 3 and 5 written in base 10. 16
0, 1, 2, 4, 26, 52, 1066, 1667, 2188, 32152, 67834, 423176, 437576, 14752936, 26513692, 27711772, 33274388, 320785556, 1065805109, 9012701786, 9256436186, 12814126552, 18814619428, 201241053056, 478999841578, 670919564984, 18432110906024, 158312796835916, 278737550525722 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,3
COMMENTS
0 is only 0 regardless of the base,
1 is only 1 regardless of the base,
2 on the other hand is also 10 in base 2, denoted as 10_2,
3 is 3 in all bases greater than 3, but is 11_2 and 10_3.
LINKS
FORMULA
Intersection of A014190 and A029952.
EXAMPLE
52 is in the sequence because 52_10 = 202_5 = 1221_3.
MATHEMATICA
(* first load nthPalindromeBase from A002113 *) palQ[n_Integer, base_Integer] := Block[{}, Reverse[ idn = IntegerDigits[n, base]] == idn]; k = 0; lst = {}; While[k < 21000000, pp = nthPalindromeBase[k, 5]; If[ palQ[pp, 3], AppendTo[lst, pp]; Print[pp]]; k++]; lst
b1=3; b2=5; lst={}; Do[d1=IntegerDigits[n, b1]; d2=IntegerDigits[n, b2]; If[d1==Reverse[d1]&&d2==Reverse[d2], AppendTo[lst, n]], {n, 0, 10000000}]; lst (* Vincenzo Librandi, Jul 15 2015 *)
PROG
(Python)
def nextpal(n, b): # returns the palindromic successor of n in base b
....m, pl = n+1, 0
....while m > 0:
........m, pl = m//b, pl+1
....if n+1 == b**pl:
........pl = pl+1
....n = (n//(b**(pl//2))+1)//(b**(pl%2))
....m = n
....while n > 0:
........m, n = m*b+n%b, n//b
....return m
n, a3, a5 = 0, 0, 0
while n <= 20000:
....if a3 < a5:
........a3 = nextpal(a3, 3)
....elif a5 < a3:
........a5 = nextpal(a5, 5)
....else: # a3 == a5
........print(n, a3)
........a3, a5, n = nextpal(a3, 3), nextpal(a5, 5), n+1
# A.H.M. Smeets, Jun 03 2019
CROSSREFS
Sequence in context: A129894 A028386 A362001 * A155120 A356442 A144691
KEYWORD
nonn,base
AUTHOR
Eric A. Schmidt and Robert G. Wilson v, Jul 14 2015
STATUS
approved

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Last modified August 13 14:39 EDT 2024. Contains 375142 sequences. (Running on oeis4.)