

A000169


Number of labeled rooted trees with n nodes: n^(n1).
(Formerly M1946 N0771)


346



1, 2, 9, 64, 625, 7776, 117649, 2097152, 43046721, 1000000000, 25937424601, 743008370688, 23298085122481, 793714773254144, 29192926025390625, 1152921504606846976, 48661191875666868481, 2185911559738696531968, 104127350297911241532841, 5242880000000000000000000
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OFFSET

1,2


COMMENTS

Also the number of connected transitive subtree acyclic digraphs on n vertices.  Robert Castelo (rcastelo(AT)imim.es), Jan 06 2001
For any given integer k, a(n) is also the number of functions from {1,2,...,n} to {1,2,...,n} such that the sum of the function values is k mod n.  Sharon Sela (sharonsela(AT)hotmail.com), Feb 16 2002
The nth term of a geometric progression with first term 1 and common ratio n: a(1) = 1 > 1,1,1,1,... a(2) = 2 > 1,2,... a(3) = 9 > 1,3,9,... a(4) = 64 > 1,4,16,64,...  Amarnath Murthy, Mar 25 2004
All rational solutions to the equation x^y = y^x, with x < y, are given by x = A000169(n+1)/A000312(n), y = A000312(n+1)/A007778(n), where n = 1, 2, 3, ... .  Nick Hobson, Nov 30 2006
In other words, if A is a finite set of size n1, then a(n) is the number of binary relations on A that are also functions. Note that a(n) = Sum_{k=0..n1} binomial(n1,k)*(n1)^k = n^(n1), where binomial(n1,k) is the number of ways to select a domain D of size k from A and (n1)^k is the number of functions from D to A.  Dennis P. Walsh, Apr 21 2011
More generally, consider the class of sequences of the form a(n) = (n*c(1)*...*c(i))^(n1). This sequence has c(1)=1. A052746 has a(n) = (2*n)^(n1), A052756 has a(n) = (3*n)^(n1), A052764 has a(n) = (4*n)^(n1), A052789 has a(n) = (5*n)^(n1) for n>0. These sequences have a combinatorial structure like simple grammars.  Ctibor O. Zizka, Feb 23 2008
a(n) is equal to the logarithmic transform of the sequence b(n) = n^(n2) starting at b(2).  Kevin Hu (10thsymphony(AT)gmail.com), Aug 23 2010
Also, number of labeled connected multigraphs of order n without cycles except one loop. See link below to have a picture showing the bijection between rooted trees and multigraphs of this kind. (Note that there are no labels in the picture, but the bijection remains true if we label the nodes.)  Washington Bomfim, Sep 04 2010
a(n) is also the number of functions f:{1,2,...,n} > {1,2,...,n} such that f(1) = 1.
For a signed version of A000169 arising from the Vandermonde determinant of (1,1/2,...,1/n), see the Mathematica section.  Clark Kimberling, Jan 02 2012
a(n+1) is the number of n x n binary matrices with no more than a single one in each row. Partitioning the set of such matrices by the number k of rows with a one, we obtain a(n+1) = Sum_{k=0..n} binomial(n,k)*n^k = (n+1)^n.  Dennis P. Walsh, May 27 2014
a(n) is the row sum of the nth rows of A248120 and A055302, so it enumerates the monomials in the expansion of [x(1) + x(2) + ... + x(n)]^(n1).  Tom Copeland, Jul 17 2015
For any given integer k, a(n) is the number of sums x_1 + ... + x_m = k (mod n) such that: x_1, ..., x_m are nonnegative integers less than n, the order of the summands does not matter, and each integer appears fewer than n times as a summand.  Carlo Sanna, Oct 04 2015
a(n) is the number of words of length n1 over an alphabet of n letters.  Joerg Arndt, Oct 07 2015
a(n) is the number of parking functions whose largest element is n and length is n. For example, a(3) = 9 because there are nine such parking functions, namely (1,2,3), (1,3,2), (2,3,1), (2,1,3), (3,1,2), (3,2,1), (1,1,3), (1,3,1), (3,1,1).  Ran Pan, Nov 15 2015
Consider the following problem: n^2 cells are arranged in a square array. A step can be defined as going from one cell to the one directly above it, to the right of it or under it. A step above cannot be followed by a step below and vice versa. Once the last column of the square array is reached, you can only take steps down. a(n) is the number of possible paths (i.e., sequences of steps) from the cell on the bottom left to the cell on the bottom right.  Nicolas Nagel, Oct 13 2016
The rationals c(n) = a(n+1)/a(n), n >= 1, appear in the proof of G. Pólya's "elementary, but not too elementary, theorem": Sum_{n>=1} (Product_{k=1..n} a_k)^(1/n) < exp(1)*Sum_{n>=1} a_n, for n >= 1, with the sequence {a_k}_{k>=1} of nonnegative terms, not all equal to 0.  Wolfdieter Lang, Mar 16 2018
Coefficients of the generating series for the preLie operadic algebra. Cf. p. 417 of the Loday et al. paper.  Tom Copeland, Jul 08 2018
a(n)/2^(n1) is the square of the determinant of the n X n matrix M_n with elements m(j,k) = cos(Pi*j*k/n). See ZhiWei Sun, Petrov link.  Hugo Pfoertner, Sep 19 2021


REFERENCES

Miklos Bona, editor, Handbook of Enumerative Combinatorics, CRC Press, 2015, page 169.
Jonathan L. Gross and Jay Yellen, eds., Handbook of Graph Theory, CRC Press, 2004; p. 524.
Hannes Heikinheimo, Heikki Mannila and Jouni K. Seppnen, Finding Trees from Unordered 01 Data, in Knowledge Discovery in Databases: PKDD 2006, Lecture Notes in Computer Science, Volume 4213/2006, SpringerVerlag.  N. J. A. Sloane, Jul 09 2009
Clifford A. Pickover, A Passion for Mathematics, Wiley, 2005; see p. 63.
John Riordan, An Introduction to Combinatorial Analysis, Wiley, 1958, p. 128.
N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
Richard P. Stanley, Enumerative Combinatorics, Cambridge, Vol. 2, 1999; see page 25, Prop. 5.3.2, and p. 37, (5.52).


LINKS

G. Pólya, With, or Without, Motivation?, Amer. Math. Monthly, Vol. 56, No. 10 (1949), pp. 684691. Reprinted in "A Century of Mathematics", John Ewing (ed.), Math. Assoc. of Amer., 1994, pp. 195200 (the reference there is wrong).


FORMULA

The e.g.f. T(x) = Sum_{n>=1} n^(n1)*x^n/n! satisfies T(x) = x*exp(T(x)), so T(x) is the functional inverse (series reversion) of x*exp(x).
Also T(x) = LambertW(x) where W(x) is the principal branch of Lambert's function.
T(x) is sometimes called Euler's tree function.
E.g.f.: LambertW(x)=x*G(0); G(k) = 1  x*((2*k+2)^(2*k))/(((2*k+1)^(2*k))  x*((2*k+1)^(2*k))*((2*k+3)^(2*k+1))/(x*((2*k+3)^(2*k+1))  ((2*k+2)^(2*k+1))/G(k+1))); (continued fraction).  Sergei N. Gladkovskii, Dec 30 2011
a(n) = Sum_{i=1..n} binomial(n1,i1)*i^(i2)*(ni)^(ni).  Dmitry Kruchinin, Oct 28 2013
Sum_{n>=1} (1)^(n+1)/a(n) = A262974. (End)
a(n) = Sum_{k=0..n1} (1)^(n+k1)*Pochhammer(n, k)*Stirling2(n1, k).  Mélika Tebni, May 07 2023


EXAMPLE

For n=3, a(3)=9 because there are exactly 9 binary relations on A={1, 2} that are functions, namely: {}, {(1,1)}, {(1,2)}, {(2,1)}, {(2,2)}, {(1,1),(2,1)}, {(1,1),(2,2)}, {(1,2),(2,1)} and {(1,2),(2,2)}.  Dennis P. Walsh, Apr 21 2011
G.f. = x + 2*x^2 + 9*x^3 + 64*x^4 + 625*x^5 + 7776*x^6 + 117649*x^7 + ...


MAPLE

# second program:
spec := [A, {A=Prod(Z, Set(A))}, labeled]; [seq(combstruct[count](spec, size=n), n=1..20)];
# third program:
A000169 := n > add((1)^(n+k1)*pochhammer(n, k)*Stirling2(n1, k), k = 0..n1):


MATHEMATICA

(* Next, a signed version A000169 from the Vandermonde determinant of (1, 1/2, ..., 1/n) *)
f[j_] := 1/j; z = 12;
v[n_] := Product[Product[f[k]  f[j], {j, 1, k  1}], {k, 2, n}]
Table[v[n], {n, 1, z}]
Table[v[n]/v[n + 1], {n, 1, z  1}] (* A000169 signed *)


PROG

(PARI) a(n) = n^(n1)
(PARI) N=66; x='x+O('x^N); egf=serreverse(x*exp(x)); Vec(serlaplace(egf)) \\ Computation via e.g.f. by series reversion of x*exp(x).  Joerg Arndt, May 25 2011
(Python)
def a(n): return n**(n1)


CROSSREFS

Cf. A000055, A000081, A000272, A000312, A007778, A007830, A008785A008791, A055860, A002061, A052746, A052756, A052764, A052789, A051129, A098686, A247363, A055302, A248120, A130293, A053506A053509, A262974.


KEYWORD

easy,core,nonn,nice,changed


AUTHOR



STATUS

approved



