OFFSET
1,1
COMMENTS
Conjecture: Apart from the initial 6, the rest of terms are the numbers k for which A003415(k) > A276086(k), thus giving the positions of zeros in A351232. In other words, it seems that only k=6 satisfies A003415(k) = A276086(k). See also comments in A351088.
From Antti Karttunen, Jan 15 2026: (Start)
Sequence A276086(A391938(.)) sorted into ascending order, thus, if the above conjecture is correct, then apart from the initial 6 this is the complement of (A000040 U A391939).
Note how the terms of this sequence seem to be rare, while those of A391938 seem to be common.
(End)
LINKS
Antti Karttunen, Table of n, a(n) for n = 1..11643 (terms up to 3*A002110(9))
Victor Ufnarovski and Bo Ã…hlander, How to Differentiate a Number, J. Integer Seqs., Vol. 6, 2003, #03.3.4.
PROG
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Antti Karttunen, Feb 05 2022
STATUS
approved
