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A175926
Sum of divisors of cubes.
15
1, 15, 40, 127, 156, 600, 400, 1023, 1093, 2340, 1464, 5080, 2380, 6000, 6240, 8191, 5220, 16395, 7240, 19812, 16000, 21960, 12720, 40920, 19531, 35700, 29524, 50800, 25260, 93600, 30784, 65535, 58560, 78300, 62400, 138811, 52060, 108600, 95200
OFFSET
1,2
COMMENTS
The Mobius transform of the sequence is 1, 14, 39 ,112, 155,..., which equals the sequence defined by n*A160889(n). - R. J. Mathar, Apr 15 2011
Zhi-Wei Sun noted that the first 10^7 terms are pairwise distinct, but Noam D. Elkies found that a(48142241) = a(48374911), a(384422506) = a(403764207) and so on. - Zhi-Wei Sun, Jan 08 2014
LINKS
FORMULA
a(n) = A000203(n^3). - R. J. Mathar, Mar 31 2011
Multiplicative with a(p^e) = (p^(3e+1)-1)/(p-1). - R. J. Mathar, Mar 31 2011
Sum_{k>=1} 1/a(k) = 1.11535899887110289127674868460900333554265894187008102863022551119560512446... - Vaclav Kotesovec, Sep 20 2020
Sum_{k=1..n} a(k) ~ c * n^4, where c = (zeta(4)/4) * Product_{p prime} (1 + 1/p^2 + 1/p^3) = 0.4732277044... . - Amiram Eldar, Nov 05 2022
MATHEMATICA
DivisorSigma[1, #]&/@((Range[40])^3) (* Harvey P. Dale, Aug 30 2015 *)
f[p_, e_] := (p^(3*e + 1) - 1)/(p - 1); a[1] = 1; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 50] (* Amiram Eldar, Sep 10 2020 *)
PROG
(Magma) [ SumOfDivisors(n^3) : n in [1..100]]; // Vincenzo Librandi, Apr 14 2011
(PARI) a(n) = sigma(n^3); \\ Amiram Eldar, Nov 05 2022
(Python)
from math import prod
from sympy import factorint
def A175926(n): return prod((p**(3*e+1)-1)//(p-1) for p, e in factorint(n).items()) # Chai Wah Wu, Oct 25 2023
CROSSREFS
Cf. sigma(n^k): A000203 (k=1), A065764 (k=2), this sequence (k=3), A202994 (k=4), A203556 (k=5).
Sequence in context: A005337 A160891 A223425 * A038991 A068020 A131991
KEYWORD
nonn,mult
AUTHOR
Zak Seidov, Oct 19 2010
STATUS
approved