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A013671 Decimal expansion of zeta(13). 10
1, 0, 0, 0, 1, 2, 2, 7, 1, 3, 3, 4, 7, 5, 7, 8, 4, 8, 9, 1, 4, 6, 7, 5, 1, 8, 3, 6, 5, 2, 6, 3, 5, 7, 3, 9, 5, 7, 1, 4, 2, 7, 5, 1, 0, 5, 8, 9, 5, 5, 0, 9, 8, 4, 5, 1, 3, 6, 7, 0, 2, 6, 7, 1, 6, 2, 0, 8, 9, 6, 7, 2, 6, 8, 2, 9, 8, 4, 4, 2, 0, 9, 8, 1, 2, 8, 9, 2, 7, 1, 3, 9, 5, 3, 2, 6, 8, 1, 3 (list; constant; graph; refs; listen; history; text; internal format)
OFFSET

1,6

REFERENCES

M. Abramowitz and I. A. Stegun, eds., Handbook of Mathematical Functions, National Bureau of Standards Applied Math. Series 55, 1964 (and various reprintings), p. 811.

LINKS

Table of n, a(n) for n=1..99.

M. Abramowitz and I. A. Stegun, eds., Handbook of Mathematical Functions, National Bureau of Standards, Applied Math. Series 55, Tenth Printing, 1972 [alternative scanned copy].

FORMULA

From Peter Bala, Dec 04 2013: (Start)

Definition: zeta(13) = sum {n >= 1} 1/n^13.

zeta(13) = 2^13/(2^13 - 1)*( sum {n even} n^9*p(n)*p(1/n)/(n^2 - 1)^14 ), where p(n) = n^6 + 21*n^4 + 35*n^2 + 7. (End)

zeta(13) = Sum_{n >= 1} (A010052(n)/n^(13/2)) = Sum_{n >= 1} ( (floor(sqrt(n))-floor(sqrt(n-1)))/n^(13/2) ). - Mikael Aaltonen, Feb 22 2015

zeta(13) = Product_{k>=1} 1/(1 - 1/prime(k)^13). - Vaclav Kotesovec, May 02 2020

EXAMPLE

1.0001227133475784891467518365263573957142751058955098451367026716208967...

MATHEMATICA

RealDigits[Zeta[13], 10, 120][[1]] (* Harvey P. Dale, Dec 24 2016 *)

PROG

(PARI) zeta(13) \\ Charles R Greathouse IV, Apr 25 2016

CROSSREFS

Cf. A013663, A013667, A013669, A013671, A013675, A013677.

Sequence in context: A201315 A199861 A190256 * A019807 A324085 A340180

Adjacent sequences:  A013668 A013669 A013670 * A013672 A013673 A013674

KEYWORD

cons,nonn

AUTHOR

N. J. A. Sloane.

STATUS

approved

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Last modified February 25 19:39 EST 2021. Contains 341618 sequences. (Running on oeis4.)