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A239053
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Sum of divisors of 4*n-1.
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8
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4, 8, 12, 24, 20, 24, 40, 32, 48, 56, 44, 48, 72, 72, 60, 104, 68, 72, 124, 80, 84, 120, 112, 120, 156, 104, 108, 152, 144, 144, 168, 128, 132, 240, 140, 168, 228, 152, 192, 216, 164, 168, 260, 248, 180, 248, 216, 192, 336, 200, 240, 312, 212, 264, 296
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OFFSET
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1,1
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COMMENTS
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a(n) is also the total number of cells in the n-th branch of the third quadrant of the spiral formed by the parts of the symmetric representation of sigma(4n-1), see example. For the quadrants 1, 2, 4 see A112610, A239052, A193553. The spiral has been obtained according to the following way: A196020 --> A236104 --> A235791 --> A237591 --> A237593 --> A237270.
We can find the spiral (mentioned above) on the terraces of the pyramid described in A244050. - Omar E. Pol, Dec 06 2016
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LINKS
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FORMULA
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Sum_{k=1..n} a(k) = (Pi^2/4) * n^2 + O(n*log(n)). - Amiram Eldar, Dec 17 2022
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EXAMPLE
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Illustration of initial terms:
-----------------------------------------------------
. Branches of the spiral
. in the third quadrant n a(n)
-----------------------------------------------------
. _ _ _ _
. | | | | | | | |
. | | | | | | |_|_ _
. | | | | | | 2 |_ _| 1 4
. | | | | |_|_ 2
. | | | | 4 |_
. | | |_|_ _ |_ _ _ _
. | | 6 |_ |_ _ _ _| 2 8
. |_|_ _ _ |_ 4
. 8 | |_ _ |
. |_ | |_ _ _ _ _ _
. |_ |_ |_ _ _ _ _ _| 3 12
. 8 |_ _| 6
. |
. |_ _ _ _ _ _ _ _
. |_ _ _ _ _ _ _ _| 4 24
. 8
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For n = 4 the sum of divisors of 4*n-1 is 1 + 3 + 5 + 15 = A000203(15) = 24. On the other hand the parts of the symmetric representation of sigma(15) are [8, 8, 8] and the sum of them is 8 + 8 + 8 = 24, equaling the sum of divisors of 15, so a(4) = 24.
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MAPLE
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MATHEMATICA
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PROG
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CROSSREFS
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Cf. A000203, A004767, A008438, A062731, A074400, A112610, A193553, A196020, A235791, A236104, A237270, A237591, A237593, A239050, A239052, A244050, A245092, A262626.
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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