|
|
A334741
|
|
Fill an infinite square array by following a spiral around the origin; in the central cell enter a(0)=1; thereafter, in the n-th cell, enter the sum of the entries of those earlier cells that are in the same row or column as that cell.
|
|
3
|
|
|
1, 1, 1, 2, 3, 5, 8, 11, 21, 40, 47, 93, 180, 203, 397, 796, 1576, 1675, 3305, 6636, 13192, 14004, 27607, 55029, 110192, 220024, 226740, 450123, 898661, 1798700, 3594248, 3704800, 7354303, 14681369, 29349536, 58710640, 117394896, 119196748, 237492079
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
0,4
|
|
COMMENTS
|
The spiral track being used here is the same as in A274640, except that the starting cell here is indexed 0 (as in A274641).
The central cell gets index 0 (and we fill it in with the value a(0)=1).
|
|
LINKS
|
|
|
EXAMPLE
|
Spiral begins:
3----2----1
| |
5 1----1 47
| |
8---11---21---40
a(11) = 47 = 1 + 1 + 5 + 40, the sum of the cells in its row and column.
|
|
PROG
|
P(n)={my(m=sqrtint(n), k=ceil(m/2)); n -= 4*k^2; if(n<0, if(n<-m, [k, 3*k+n], [-k-n, k]), if(n<m, [-k, k-n], [n-3*k, -k]))}
seq(n)={my(m=sqrtint(n)+1, k=ceil(m/2), sx=vector(m), sy=vector(m), v=vector(1+n)); v[1]=sx[k]=sy[k]=1; for(i=1, n, my([px, py]=P(i)); px+=k; py+=k; my(t=sx[px]+sy[py]); sx[px]+=t; sy[py]+=t; v[i+1]=t); v} \\ Andrew Howroyd, May 09 2020
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|