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A122840
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a(n) is the number of 0's at the end of n when n is written in base 10.
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40
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0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0
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OFFSET
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1,100
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COMMENTS
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Greatest k such that 10^k divides n.
a(n) = the number of digits in n - A160093(n).
a(A005117(n)) <= 1. - Reinhard Zumkeller, Mar 30 2010
See A054899 for the partial sums. - Hieronymus Fischer, Jun 08 2012
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LINKS
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Reinhard Zumkeller, Table of n, a(n) for n = 1..10000
S. Ikeda and K. Matsuoka, On transcendental numbers generated by certain integer sequences, Siauliai Math. Semin., 8 (16) 2013, 63-69.
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FORMULA
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a(n) = A160094(n) - 1.
From Hieronymus Fischer, Jun 08 2012: (Start)
With m = floor(log_10(n)), frac(x) = x-floor(x):
a(n) = Sum_{j=1..m} (1 - ceiling(frac(n/10^j))).
a(n) = m + Sum_{j=1..m} (floor(-frac(n/10^j))).
a(n) = A054899(n) - A054899(n-1).
G.f.: g(x) = Sum_{j>0} x^10^j/(1-x^10^j). (End)
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EXAMPLE
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a(160) = 1 because there is 1 zero at the end of 160 when 160 is written in base 10.
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PROG
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(Haskell)
a122840 n = if n < 10 then 0 ^ n else 0 ^ d * (a122840 n' + 1)
where (n', d) = divMod n 10
-- Reinhard Zumkeller, Mar 09 2013
(PARI) a(n)=valuation(n, 10) \\ Charles R Greathouse IV, Feb 26 2014
(Python)
def a(n): return len(str(n)) - len(str(int(str(n)[::-1]))) # Indranil Ghosh, Jun 09 2017
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CROSSREFS
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A007814 is the base 2 equivalent of this sequence.
Cf. A160094, A160093, A001511, A070940, A122841, A027868, A054899, A196563, A196564, A004151.
Sequence in context: A118553 A102448 A102683 * A083919 A063665 A276306
Adjacent sequences: A122837 A122838 A122839 * A122841 A122842 A122843
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KEYWORD
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nonn,base,easy
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AUTHOR
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Reinhard Zumkeller, Sep 13 2006
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STATUS
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approved
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