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 A122841 Greatest k such that 6^k divides n. 48
 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,36 COMMENTS See A054895 for the partial sums. - Hieronymus Fischer, Jun 08 2012 LINKS Reinhard Zumkeller, Table of n, a(n) for n = 1..10000 FORMULA From Hieronymus Fischer, Jun 03 2012: (Start) With m = floor(log_6(n)), frac(x) = x-floor(x): a(n) = Sum_{j=1..m} (1 - ceiling(frac(n/6^j))). a(n) = m + Sum_{j=1..m} (floor(-frac(n/6^j))). a(n) = A054895(n) - A054895(n-1). G.f.: Sum_{j>0} x^6^j/(1-x^6^j). (End) a(A047253(n)) = 0; a(A008588(n)) > 0; a(A044102(n)) > 1. - Reinhard Zumkeller, Nov 10 2013 6^a(n) = A234959(n), n >= 1. - Wolfdieter Lang, Jun 30 2014 Asymptotic mean: lim_{m->oo} (1/m) * Sum_{k=1..m} a(k) = 1/5. - Amiram Eldar, Jan 17 2022 a(n) = min(A007814(n), A007949(n)). - Jianing Song, Jul 23 2022 MATHEMATICA Table[IntegerExponent[n, 6], {n, 1, 100}] (* Amiram Eldar, Sep 14 2020 *) PROG (Haskell) a122841 = f 0 where f y x = if r > 0 then y else f (y + 1) x' where (x', r) = divMod x 6 -- Reinhard Zumkeller, Nov 10 2013 (PARI) a(n) = valuation(n, 6); \\ Michel Marcus, Jan 17 2022 CROSSREFS Cf. A122840, A007814, A007949, A054895, A234959. Sequence in context: A070205 A138363 A080225 * A326075 A060862 A325801 Adjacent sequences: A122838 A122839 A122840 * A122842 A122843 A122844 KEYWORD nonn AUTHOR Reinhard Zumkeller, Sep 13 2006 STATUS approved

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Last modified December 6 09:57 EST 2022. Contains 358617 sequences. (Running on oeis4.)