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A060280
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Number of orbits of length n under the map whose periodic points are counted by A001350.
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11
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1, 0, 1, 1, 2, 2, 4, 5, 8, 11, 18, 25, 40, 58, 90, 135, 210, 316, 492, 750, 1164, 1791, 2786, 4305, 6710, 10420, 16264, 25350, 39650, 61967, 97108, 152145, 238818, 374955, 589520, 927200, 1459960, 2299854, 3626200, 5720274, 9030450, 14263078, 22542396
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OFFSET
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1,5
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COMMENTS
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Euler transform is A000045. 1/((1-x)*(1-x^3)*(1-x^4)*(1-x^5)^2*(1-x^6)^2*...) = 1 + x + x^2 + 2*x^3 + 3*x^4 + 5*x^5 + 8*x^6 + ... - Michael Somos, Jan 28 2003
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LINKS
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FORMULA
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a(n) = (1/n)* Sum_{d|n} mu(d)*A001350(n/d).
G.f.: Sum_{k>=1} mu(k)*log(1 + x^k/(1 - x^k - x^(2*k)))/k. - Ilya Gutkovskiy, May 18 2019
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EXAMPLE
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a(7)=4 since the 7th term of A001350 is 29 and the 1st is 1, so there are (29-1)/7 = 4 orbits of length 7.
x + x^3 + x^4 + 2*x^5 + 2*x^6 + 4*x^7 + 5*x^8 + 8*x^9 + 11*x^10 + 18*x^11 + ...
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MAPLE
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add( numtheory[mobius](d)*A001350(n/d), d=numtheory[divisors](n)) ;
%/n;
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MATHEMATICA
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a001350[n_] := Fibonacci[n - 1] + Fibonacci[n + 1] - (-1)^n - 1;
a[n_] := (1/n)*DivisorSum[n, MoebiusMu[#]*a001350[n/#]& ];
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PROG
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(PARI) {a(n) = if( n<3, n==1, sumdiv( n, d, moebius(n/d) * (fibonacci(d - 1) + fibonacci(d + 1))) / n)} /* Michael Somos, Jan 28 2003 */
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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STATUS
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approved
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