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A001093
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a(n) = n^3 + 1.
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46
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0, 1, 2, 9, 28, 65, 126, 217, 344, 513, 730, 1001, 1332, 1729, 2198, 2745, 3376, 4097, 4914, 5833, 6860, 8001, 9262, 10649, 12168, 13825, 15626, 17577, 19684, 21953, 24390, 27001, 29792, 32769, 35938, 39305, 42876, 46657, 50654, 54873, 59320
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OFFSET
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-1,3
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COMMENTS
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Nonnegative X values of solutions to the equation 1!*X^4 + 2!*(X - 1)^3 + 3!*(X - 2)^2 + (4^2)*(X - 3) + 5^2 = Y^3. To prove that X = n^3 + 1: Y^3 = 1!*X^4 + 2!*(X - 1)^3 + 3!*(X - 2)^2 + (4^2)*(X -3) + 5^2 = X^4 + 2*(X - 1)^3 + 6*(X - 2)^2 + 16(X -3) + 25 = X^4 + 2*X^3 - 2X - 1 = (X - 1)(X^3 + 3*X^2 + 3X + 1) = (X - 1)*(X + 1)^3 it means: (X - 1) must be a cube, so X = n^3 + 1 and Y = n(n^3 + 2). - Mohamed Bouhamida, Dec 04 2007
Where records occur in the (real) sequence ceiling(k^(1/3)) - k^(1/3), k = 1, 2, 3, ... . - John W. Layman, Sep 07 2010
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LINKS
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FORMULA
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Sum_{n>=1} 1/a(n) = 1/2 + Sum_{n>=1} (-1)^(n+1) * (zeta(3*n) - 1) = 0.6865033423... - Amiram Eldar, Nov 06 2020
Product_{n>=1} (1 - 1/a(n)) = Pi*sech(sqrt(3)*Pi/2). - Amiram Eldar, Jan 20 2021
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MAPLE
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MATHEMATICA
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LinearRecurrence[{4, -6, 4, -1}, {0, 1, 2, 9}, 50] (* Harvey P. Dale, May 14 2017 *)
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PROG
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(Haskell)
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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