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A369679
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a(n) = Product_{k=0..n} (3^k + 4^(n-k)).
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5
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2, 20, 1190, 449540, 1094267450, 17283181758500, 1774660248586902950, 1182579046508766038251700, 5134581376819479940742838299450, 144547890423248529154421336209389168500, 26527720524980501045637796065988864058001683750, 31574745853363739268697794406696294745967395732336262500
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OFFSET
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0,1
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LINKS
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FORMULA
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a(n) = Product_{k=0..n} (3^k + 4^(n-k)).
a(n) = 12^(n*(n+1)/2) * Product_{k=0..n} (1/3^k + 1/4^(n-k)).
a(n) = 4^(n*(n+1)/2) * Product_{k=0..n} (1 + 3^n/12^k).
a(n) = 3^(n*(n+1)/2) * Product_{k=0..n} (1 + 4^n/12^k).
a(n) = 3^(-n*(n+1)/2) * Product_{k=0..n} (3^n + 12^k).
a(n) = 4^(-n*(n+1)/2) * Product_{k=0..n} (4^n + 12^k).
a(n) = 3^(n*(n+1)/2)*QPochhammer(-4^n, 1/12, n + 1). - Stefano Spezia, Feb 07 2024
Limit_{n->oo} a(n)^(1/n^2) = 3^(1/(2*(1 + log(4)/log(3)))) * 2 = 2^(1/(1 + log(3)/log(4))) * sqrt(3) = 2.54977004574388327607102436919328599299374003... - Vaclav Kotesovec, Feb 07 2024
Equivalently, limit_{n->oo} a(n)^(1/n^2) = exp((1/2) * (log(3)^2 + log(3)*log(4) + log(4)^2) / log(12)). - Paul D. Hanna, Feb 08 2024
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EXAMPLE
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a(0) = (1 + 1) = 2;
a(1) = (1 + 4)*(3 + 1) = 20;
a(2) = (1 + 4^2)*(3 + 4)*(3^2 + 1) = 1190;
a(3) = (1 + 4^3)*(3 + 4^2)*(3^2 + 4)*(3^3 + 1) = 449540;
a(4) = (1 + 4^4)*(3 + 4^3)*(3^2 + 4^2)*(3^3 + 4)*(3^4 + 1) = 1094267450;
a(5) = (1 + 4^5)*(3 + 4^4)*(3^2 + 4^3)*(3^3 + 4^2)*(3^4 + 4)*(3^5 + 1) = 17283181758500;
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RELATED SERIES.
Sum_{n>=0} Product_{k=0..n} (1/3^k + 1/4^(n-k)) = 2 + 20/12 + 1190/12^3 + 449540/12^6 + 1094267450/12^10 + 17283181758500/12^15 + ... + a(n)/12^(n*(n+1)/2) + ... = 4.5247082137580440222914164418070212438323...
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PROG
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(PARI) {a(n) = prod(k=0, n, 3^k + 4^(n-k))}
for(n=0, 15, print1(a(n), ", "))
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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