|
|
A368414
|
|
Number of factorizations of n into positive integers > 1 such that it is possible to choose a different prime factor of each factor.
|
|
37
|
|
|
1, 1, 1, 1, 1, 2, 1, 1, 1, 2, 1, 3, 1, 2, 2, 1, 1, 3, 1, 3, 2, 2, 1, 4, 1, 2, 1, 3, 1, 5, 1, 1, 2, 2, 2, 5, 1, 2, 2, 4, 1, 5, 1, 3, 3, 2, 1, 5, 1, 3, 2, 3, 1, 4, 2, 4, 2, 2, 1, 9, 1, 2, 3, 1, 2, 5, 1, 3, 2, 5, 1, 6, 1, 2, 3, 3, 2, 5, 1, 5, 1, 2, 1, 9, 2, 2, 2
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,6
|
|
COMMENTS
|
For example, the factorization f = 2*3*6 has two ways to choose a prime factor of each factor, namely (2,3,2) and (2,3,3), but neither of these has all different elements, so f is not counted under a(36).
|
|
LINKS
|
|
|
FORMULA
|
|
|
EXAMPLE
|
The a(n) factorizations for selected n:
1 6 12 24 30 60 72 120
2*3 2*6 2*12 2*15 2*30 2*36 2*60
3*4 3*8 3*10 3*20 3*24 3*40
4*6 5*6 4*15 4*18 4*30
2*3*5 5*12 6*12 5*24
6*10 8*9 6*20
2*3*10 8*15
2*5*6 10*12
3*4*5 2*3*20
2*5*12
2*6*10
3*4*10
3*5*8
4*5*6
|
|
MATHEMATICA
|
facs[n_]:=If[n<=1, {{}}, Join @@ Table[Map[Prepend[#, d]&, Select[facs[n/d], Min@@#>=d&]], {d, Rest[Divisors[n]]}]];
Table[Length[Select[facs[n], Select[Tuples[First/@FactorInteger[#]&/@#], UnsameQ@@#&]!={}&]], {n, 100}]
|
|
CROSSREFS
|
The complement is counted by A368413.
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|