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A133686 Number of labeled n-node graphs with at most one cycle in each connected component. 90
1, 1, 2, 8, 57, 608, 8524, 145800, 2918123, 66617234, 1704913434, 48300128696, 1499864341015, 50648006463048, 1847622972848648, 72406232075624192, 3033607843748296089, 135313823447621913500, 6402077421524339766058, 320237988317922139148736 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,3
COMMENTS
The total number of those graphs of order 5 is 608. The number of forests of trees on n labeled nodes of order 5 is 291, so the majority of the graphs of that kind have one or more unicycles.
Also the number of labeled graphs with n vertices satisfying a strict version of the axiom of choice. The axiom of choice says that, given any set of nonempty sets Y, it is possible to choose a set containing an element from each. The strict version requires this set to have the same cardinality as Y, meaning no element is chosen more than once. The connected case is A129271, complement A140638. The unlabeled version is A134964. - Gus Wiseman, Dec 22 2023
LINKS
Wikipedia, Pseudoforest
FORMULA
a(0) = 1; for n >=1, a(n) = Sum of n!prod_{j=1}^n\{ frac{ A129271(j)^{c_j} } { j!^{c_j}c_j! } } over all the partitions of n, c_1 + 2c_2 + ... + nc_n; c_1, c_2, ..., c_n >= 0.
a(n) = Sum_{k=0..n} A144228(n,k). - Alois P. Heinz, Sep 15 2008
E.g.f.: sqrt(-LambertW(-x)/(x*(1+LambertW(-x))))*exp(-3/4 * LambertW(-x)^2). - Vladeta Jovovic, Sep 16 2008
E.g.f.: A(x)*B(x) where A(x) is the e.g.f. for A137916 and B(x) is the e.g.f. for A001858. - Geoffrey Critzer, Mar 23 2013
a(n) ~ 2^(-1/4) * Gamma(3/4) * exp(-1/4) * n^(n-1/4) / sqrt(Pi) * (1-7*Pi/(12*Gamma(3/4)^2*sqrt(n))). - Vaclav Kotesovec, Oct 08 2013
E.g.f.: exp(B(x) - 1) where B(x) is the e.g.f. of A129271. - Andrew Howroyd, Dec 30 2023
EXAMPLE
Below we see the 7 partitions of n=5 in the form c_1 + 2c_2 + ... + nc_n followed by the corresponding number of graphs. We consider the values of A129271(j) given by the table
j|1|2|3| 4| 5|
----+-+-+-+--+---+
a(j)|1|1|4|31|347|
1*5 -> 5!1^5 / (1!^5 * 5!) = 1
2*1 + 1*3 -> 5!1^1 * 1^3 / (2!^1 * 1! * 1!^3 * 3!) = 10
2*2 + 1*1 -> 5!1^2 * 1^1 / (2!^2 * 2! * 1!^1 * 1!) = 15
3*1 + 1*2 -> 5!4^1 * 1^2 / (3!^1 * 1! * 1!^2 * 2!) = 40
3*1 + 2*1 -> 5!4^1 * 1^1 / (3!^1 * 1! * 2!^1 * 1!) = 40
4*1 + 1*1 -> 5!31^1 * 1^1 / (4!^1 * 1! * 1!^1 * 1!) = 155
5*1 -> 5!347^1 / (5!^1 * 1!) = 347
Total 608
MAPLE
cy:= proc(n) option remember; binomial(n-1, 2)*
add((n-3)!/(n-2-t)! *n^(n-2-t), t=1..n-2)
end:
T:= proc(n, k) option remember;
if k=0 then 1
elif k<0 or n<k then 0
else add(binomial(n-1, j)*((j+1)^(j-1)*T(n-j-1, k-j)
+cy(j+1)*T(n-j-1, k-j-1)), j=0..k)
fi
end:
a:= n-> add(T(n, k), k=0..n):
seq(a(n), n=0..20); # Alois P. Heinz, Sep 15 2008
MATHEMATICA
nn=20; t=Sum[n^(n-1)x^n/n!, {n, 1, nn}]; Range[0, nn]!CoefficientList[ Series[ Exp[t/2-3t^2/4]/(1-t)^(1/2), {x, 0, nn}], x] (* Geoffrey Critzer, Sep 05 2012 *)
Table[Length[Select[Subsets[Subsets[Range[n], {2}]], Select[Tuples[#], UnsameQ@@#&]!={}&]], {n, 0, 5}] (* Gus Wiseman, Dec 22 2023 *)
PROG
(PARI) x='x+O('x^50); Vec(serlaplace(sqrt(-lambertw(-x)/(x*(1+ lambertw(-x))))*exp(-(3/4)*lambertw(-x)^2))) \\ G. C. Greubel, Nov 16 2017
CROSSREFS
Row sums of triangle A144228. - Alois P. Heinz, Sep 15 2008
Cf. A137352. - Vladeta Jovovic, Sep 16 2008
The unlabeled version is A134964.
The complement is counted by A367867, covering A367868, connected A140638.
The covering case is A367869, connected A129271.
For set-systems we have A367902, ranks A367906.
The complement for set-systems is A367903, ranks A367907.
A006125 counts graphs, A000088 unlabeled.
A006129 counts covering graphs, A002494 unlabeled.
A143543 counts graphs by number of connected components.
Sequence in context: A153529 A153558 A027335 * A369193 A369192 A153525
KEYWORD
easy,nonn
AUTHOR
Washington Bomfim, May 12 2008
EXTENSIONS
Corrected and extended by Alois P. Heinz and Vladeta Jovovic, Sep 15 2008
STATUS
approved

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Last modified April 25 05:18 EDT 2024. Contains 371964 sequences. (Running on oeis4.)