OFFSET
1,2
COMMENTS
Odd bisection of A361891.
Conjecture: the supercongruence a(n*p^r) == a(n*p^(r-1)) (mod p^(3*r)) holds for positive integers n and r and all primes p >= 5.
LINKS
Seiichi Manyama, Table of n, a(n) for n = 1..282
FORMULA
a(n) = 1/binomial(2*n-1,n-1) * Sum_{k = 0..n-1} ( (2*n - 2*k)/(2*n - k) * binomial(2*n-1,k) )^7 for n >= 1.
a(n) ~ 3 * 2^(12*n+1) / (2401 * Pi^3 * n^6). - Vaclav Kotesovec, Mar 24 2025
MAPLE
seq(add( ( binomial(2*n-1, k) - binomial(2*n-1, k-1) )^7/binomial(2*n-1, n-1), k = 0..n-1), n = 1..20);
MATHEMATICA
Table[Sum[(Binomial[2*n-1, k]-Binomial[2*n-1, k-1])^7 / Binomial[2*n-1, n-1], {k, 0, n-1}], {n, 1, 20}] (* Vaclav Kotesovec, Mar 24 2025 *)
PROG
(Python)
from math import comb
def A361892(n): return sum((comb((n<<1)-1, j)*(m:=n-j<<1)//(m+j))**7 for j in range(n))//comb((n<<1)-1, n-1) # Chai Wah Wu, Mar 25 2025
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Peter Bala, Mar 30 2023
EXTENSIONS
Offset changed to 1 by Georg Fischer, Nov 20 2024
STATUS
approved
