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A302612 a(n) = (n+1)*(n^4-4*n^3+11*n^2-8*n+12)/12. 5
1, 2, 6, 20, 65, 186, 462, 1016, 2025, 3730, 6446, 10572, 16601, 25130, 36870, 52656, 73457, 100386, 134710, 177860, 231441, 297242, 377246, 473640, 588825, 725426, 886302, 1074556, 1293545, 1546890, 1838486, 2172512, 2553441, 2986050, 3475430, 4026996 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,2
COMMENTS
The limit as q->1^- of the unimodal polynomial [q^(n*k+n+4)-q^(n*k+n+3)+q^(n*k+n+1)-q^(n*k+4)-q^((n-1)*k+n+3)+q^((n-1)*k+3)+q^(k+n+1)-q^(k+1)-q^n+q^3-q+1]/[(1-q)^2(1-q^2)(1-q^n)] after making the simplification k=n. This unimodal polynomial is from O'Hara's proof of unimodality of q-binomials after making the restriction to partitions of size <=2. See G_2(n,k) from arXiv:1711.11252.
As the size restriction s increases, G_s->G_infinity=G: the q-binomials. Then substituting k=n and q=1 yields the central binomial coefficients: A000984.
LINKS
Bryan Ek, q-Binomials and related symmetric unimodal polynomials, arXiv:1711.11252 [math.CO], 2017-2018.
FORMULA
From Colin Barker, Apr 11 2018: (Start)
G.f.: (1 - 4*x + 9*x^2 - 6*x^3 + 10*x^4) / (1 - x)^6.
a(n) = 6*a(n-1) - 15*a(n-2) + 20*a(n-3) - 15*a(n-4) + 6*a(n-5) - a(n-6) for n>5.
(End)
EXAMPLE
For n=4, G_2(4,4)=q^16+q^15+2*q^14+3*q^13+5*q^12+5*q^11+6*q^10+6*q^9+7*q^8+6*q^7+6*q^6+5*q^5+5*q^4+3*q^3+2*q^2+q+1 (using the formula in the comments). Then substituting q=1 yields 65.
PROG
(PARI) Vec((1 - 4*x + 9*x^2 - 6*x^3 + 10*x^4) / (1 - x)^6 + O(x^40)) \\ Colin Barker, Apr 11 2018
CROSSREFS
Sequence in context: A220874 A273902 A181301 * A005726 A148473 A000718
KEYWORD
nonn,easy
AUTHOR
Bryan T. Ek, Apr 10 2018
EXTENSIONS
More terms from Colin Barker, Apr 11 2018
STATUS
approved

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Last modified March 29 11:45 EDT 2024. Contains 371278 sequences. (Running on oeis4.)