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A277698
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a(n) = least unitary prime divisor of n or 1 if no such prime-divisor exists.
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5
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1, 2, 3, 1, 5, 2, 7, 1, 1, 2, 11, 3, 13, 2, 3, 1, 17, 2, 19, 5, 3, 2, 23, 3, 1, 2, 1, 7, 29, 2, 31, 1, 3, 2, 5, 1, 37, 2, 3, 5, 41, 2, 43, 11, 5, 2, 47, 3, 1, 2, 3, 13, 53, 2, 5, 7, 3, 2, 59, 3, 61, 2, 7, 1, 5, 2, 67, 17, 3, 2, 71, 1, 73, 2, 3, 19, 7, 2, 79, 5, 1, 2, 83, 3, 5, 2, 3, 11, 89, 2, 7, 23, 3, 2, 5, 3, 97, 2, 11, 1, 101, 2, 103, 13, 3
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OFFSET
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1,2
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LINKS
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FORMULA
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MATHEMATICA
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Table[If[Length@ # == 0, 1, First@ #] &@ Select[FactorInteger[n][[All, 1]], GCD[#, n/#] == 1 &], {n, 105}] (* Michael De Vlieger, Oct 30 2016 *)
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PROG
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(Python)
from sympy import factorint, prime, primepi, isprime, primefactors
def a049084(n): return primepi(n)*(1*isprime(n))
def a055396(n): return 0 if n==1 else a049084(min(primefactors(n)))
def a028234(n):
f = factorint(n)
return 1 if n==1 else n/(min(f)**f[min(f)])
def a067029(n):
f=factorint(n)
return 0 if n==1 else f[min(f)]
def a277697(n): return 0 if n==1 else a055396(n) if a067029(n)==1 else a277697(a028234(n))
def a008578(n): return 1 if n==1 else prime(n - 1)
def a(n): return a008578(1 + a277697(n)) # Indranil Ghosh, May 16 2017
(PARI) a(n) = {my(f = factor(n)); for(i = 1, #f~, if(f[i, 2] == 1, return(f[i, 1]))); 1; } \\ Amiram Eldar, Jul 28 2024
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CROSSREFS
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Cf. A080368 for a variant which gives 0's instead of 1's for numbers with no unitary prime divisors and also A277708 (the least prime factor with an odd exponent).
Differs from A134194 for the first time at n=18, where a(18) = 2, while A134194(18) = 3.
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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