A270355 Denominators of r-Egyptian fraction expansion for e - 2, where r = (1, 1/2, 1/4, 1/8, ...)

2, 3, 5, 78, 4962, 15925310, 303532967750376, 72884922416996896007616951849, 3238110775186648021853203185875679911508503009261997468560, 7716186732679740909751872277405382774000613384297298421745471878603639986756704754013029661605882827711280194233739

Offset

1,1

Comments

Suppose that r is a sequence of rational numbers r(k) <= 1 for k >= 1, and that x is an irrational number in (0,1). Let f(0) = x, n(k) = floor(r(k)/f(k-1)), and f(k) = f(k-1) - r(k)/n(k). Then x = r(1)/n(1) + r(2)/n(2) + r(3)/n(3) + ..., the r-Egyptian fraction for x.

See A269993 for a guide to related sequences.

Links

Clark Kimberling, Table of n, a(n) for n = 1..12

Eric Weisstein's World of Mathematics, Egyptian Fraction

Index entries for sequences related to Egyptian fractions

Example

1/e = 1/2 + 1/(2*3) + 1/(4*5) + ...

Mathematica

r[k_] := 2/2^k; f[x_, 0] = x; z = 10;
n[x_, k_] := n[x, k] = Ceiling[r[k]/f[x, k - 1]]
f[x_, k_] := f[x, k] = f[x, k - 1] - r[k]/n[x, k]
x = E - 2; Table[n[x, k], {k, 1, z}]

Prog

(PARI) r(k) = 2/2^k;
f(k, x) = if (k==0, x, f(k-1, x) - r(k)/a(k, x); );
a(k, x=exp(1)-2) = ceil(r(k)/f(k-1, x));

Crossrefs

Cf. A269993.

Sequence in context: A270916 A029975 A042787 * A041131 A084960 A087543

Adjacent sequences: A270352 A270353 A270354 * A270356 A270357 A270358

Keyword

nonn,frac,easy

Author

Clark Kimberling, Mar 17 2016

Status

approved