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A240264
Decimal expansion of Sum_{n >= 1} (-1)^(n+1)*H(n,2)/n, where H(n,2) = A007406(n)/A007407(n) is the n-th harmonic number of order 2.
2
6, 3, 1, 9, 6, 6, 1, 9, 7, 8, 3, 8, 1, 6, 7, 9, 0, 6, 6, 6, 2, 4, 4, 8, 2, 3, 2, 0, 1, 5, 2, 7, 5, 3, 1, 8, 1, 5, 6, 6, 7, 1, 3, 7, 1, 6, 5, 8, 1, 7, 2, 7, 5, 5, 5, 1, 5, 2, 6, 0, 5, 6, 7, 9, 6, 5, 4, 1, 1, 7, 6, 9, 2, 0, 9, 4, 1, 5, 6, 9, 6, 2, 9, 4, 2, 9, 3, 3, 6, 4, 7, 8, 5, 5, 6, 9, 1, 4, 3, 0
OFFSET
0,1
COMMENTS
Let a(p,q) = Sum_{n >= 1} (-1)^(n+1)*H(n,p)/n^q, then A076788 is a(1,1), A233090 is a(1,2) and this sequence is a(2,1).
Original name: "Decimal expansion of Sum_{n >= 1} (-1)^(n+1)*H(n,2)/n^2, where H(n,2) is the n-th harmonic number of order 2", which is now the name of A396736. - Amiram Eldar, Jun 04 2026
REFERENCES
Bruce C. Berndt, Ramanujan's Notebooks Part I, Springer-Verlag, 1985. See p. 258, eq. (i).
Ali Shadhar Olaikhan, An Introduction to the Harmonic Series and Logarithmic Integrals, 2021, p. 252, eq. (4.162).
LINKS
Cornel Ioan Vălean, (Almost) Impossible Integrals, Sums, and Series, Springer International Publishing, 2019, section 4.51, p. 308, eq. (4.80), section 5.51, p. 326, section 6.51, pp. 498-502.
Cornel Ioan Vălean, More (Almost) Impossible Integrals, Sums, and Series, Springer Cham, 2023. See section 4.22, p. 424.
Eric Weisstein's World of Mathematics, Harmonic Number, eq. (42).
FORMULA
Equals zeta(3) - Pi^2/12*log(2).
Equals Sum_{n >= 1} (1/2)^n * H(n,1)/n^2, where H(n,1) = Sum_{k = 1..n} 1/k. See Berndt, p. 258. - Peter Bala, Oct 28 2021
EXAMPLE
0.631966197838167906662448232015275318156671371658172...
MATHEMATICA
Zeta[3] - Pi^2/12*Log[2] // RealDigits[#, 10, 100]& // First
PROG
(PARI) zeta(3)-log(2)*Pi^2/12 \\ Charles R Greathouse IV, Apr 03 2014
KEYWORD
nonn,cons
AUTHOR
EXTENSIONS
Name corrected by Amiram Eldar, Jun 04 2026 and Jun 18 2026
STATUS
approved