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A186362
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Number of non-up-down cycles in all permutations of {1,2,...,n}. A cycle (b(1), b(2), ...) is said to be up-down if, when written with its smallest element in the first position, it satisfies b(1)<b(2)>b(3)<... .
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2
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0, 0, 0, 1, 8, 59, 458, 3865, 35688, 360127, 3956214, 47096633, 604722604, 8337692687, 122932350162, 1930964182649, 32201197533072, 568323756438079, 10585305178638446, 207520767220183033, 4272031355927379828, 92145190111463378863, 2078280173125850650890
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OFFSET
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0,5
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LINKS
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FORMULA
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E.g.f.: log( (1-sin(z))/(1-z) ) / (1-z).
a(n) = n!*Sum(((j-1)!-E(j-1))/j!, j=1..n), where E(i)=A000111(i) are the Euler (or up-down) numbers.
a(n) ~ n! * (log(n) + gamma + log(1-sin(1))), where gamma is the Euler-Mascheroni constant (A001620). - Vaclav Kotesovec, Oct 02 2013
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EXAMPLE
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a(3) = 10 because the permutations (1)(2)(3), (12)(3), (13)(2), (1)(23), (132), and (123) have a total of 3 + 2 + 2 + 2 + 0 + 1 = 10 up-down cycles.
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MAPLE
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g := ln((1-sin(z))/(1-z))/(1-z): gser := series(g, z = 0, 25): seq(factorial(n)*coeff(gser, z, n), n = 0 .. 22);
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MATHEMATICA
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CoefficientList[Series[Log[(1-Sin[x])/(1-x)]/(1-x), {x, 0, 20}], x]* Range[0, 20]! (* Vaclav Kotesovec, Oct 02 2013 *)
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PROG
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(PARI) x='x+O('x^30); concat(vector(3), Vec(serlaplace(log((1-sin(x))/(1-x))/(1-x)))) \\ G. C. Greubel, Aug 30 2018
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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