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A179269
Number of partitions of n into distinct parts such that the successive differences of consecutive parts are increasing, and first difference > first part.
13
1, 1, 1, 1, 2, 2, 2, 3, 3, 3, 5, 5, 5, 7, 7, 7, 10, 10, 10, 13, 14, 14, 18, 19, 19, 23, 25, 25, 30, 32, 33, 38, 41, 42, 48, 52, 54, 60, 65, 67, 75, 81, 84, 92, 99, 103, 113, 121, 126, 136, 147, 153, 165, 177, 184, 197, 213, 221, 236, 253, 264, 280, 301, 313, 331, 355, 371, 390, 418, 435, 458
OFFSET
0,5
COMMENTS
Conditions as in A179254; additionally, if more than 1 part, first difference > first part.
Equivalently, number of partitions for which the sequence of part counts by decreasing part size is 1, 2, 3, ... - Olivier Gérard, Jul 28 2017
FORMULA
G.f.: Sum_{k>=0} x^(k*(k+1)*(k+2)/6) / Product_{j=1..k} (1 - x^(j*(j+1)/2)) (conjecture). - Ilya Gutkovskiy, Apr 25 2019
EXAMPLE
a(10) = 5 as there are 5 such partitions of 10: 1 + 3 + 6 = 1 + 9 = 2 + 8 = 3 + 7 = 10.
a(10) = 5 as there are 5 such partitions of 10: 10, 8 + 1 + 1, 6 + 2 + 2, 4 + 3 + 3, 3 + 2 + 2 + 1 + 1 + 1 (second definition).
From Gus Wiseman, May 04 2019: (Start)
The a(3) = 1 through a(13) = 7 partitions whose differences are strictly increasing (with the last part taken to be 0) are the following (A = 10, B = 11, C = 12, D = 13). The Heinz numbers of these partitions are given by A325460.
(3) (4) (5) (6) (7) (8) (9) (A) (B) (C) (D)
(31) (41) (51) (52) (62) (72) (73) (83) (93) (94)
(61) (71) (81) (82) (92) (A2) (A3)
(91) (A1) (B1) (B2)
(631) (731) (831) (C1)
(841)
(931)
The a(3) = 1 through a(11) = 5 partitions whose multiplicities form an initial interval of positive integers are the following (A = 10, B = 11). The Heinz numbers of these partitions are given by A307895.
(3) (4) (5) (6) (7) (8) (9) (A) (B)
(211) (311) (411) (322) (422) (522) (433) (533)
(511) (611) (711) (622) (722)
(811) (911)
(322111) (422111)
(End)
MATHEMATICA
Table[Length@
Select[IntegerPartitions[n],
And @@ Equal[Range[Length[Split[#]]], Length /@ Split[#]] &], {n,
0, 40}] (* Olivier Gérard, Jul 28 2017 *)
Table[Length[Select[IntegerPartitions[n], Less@@Differences[Append[#, 0]]&]], {n, 0, 30}] (* Gus Wiseman, May 04 2019 *)
PROG
(Sage)
def A179269(n):
has_increasing_diffs = lambda x: min(differences(x, 2)) >= 1
special = lambda x: (x[1]-x[0]) > x[0]
allowed = lambda x: (len(x) < 2 or special(x)) and (len(x) < 3 or has_increasing_diffs(x))
return len([x for x in Partitions(n, max_slope=-1) if allowed(x[::-1])])
# D. S. McNeil, Jan 06 2011
(Ruby)
def partition(n, min, max)
return [[]] if n == 0
[max, n].min.downto(min).flat_map{|i| partition(n - i, min, i - 1).map{|rest| [i, *rest]}}
end
def f(n)
return 1 if n == 0
cnt = 0
partition(n, 1, n).each{|ary|
ary << 0
ary0 = (1..ary.size - 1).map{|i| ary[i - 1] - ary[i]}
cnt += 1 if ary0.sort == ary0.reverse && ary0.uniq == ary0
}
cnt
end
def A179269(n)
(0..n).map{|i| f(i)}
end
p A179269(50) # Seiichi Manyama, Oct 12 2018
(PARI)
R(n)={my(L=List(), v=vectorv(n, i, 1), w=1, t=1); while(v, listput(L, v); w++; t+=w; v=vectorv(n, i, sum(k=1, (i-1)\t, L[w-1][i-k*t]))); Mat(L)}
seq(n)={my(M=R(n)); concat([1], vector(n, i, vecsum(M[i, ])))} \\ Andrew Howroyd, Aug 27 2019
CROSSREFS
Cf. A179254 (condition only on differences), A007294 (nondecreasing instead of strictly increasing), A179255, A320382, A320385, A320387, A320388.
Sequence in context: A008649 A008650 A062051 * A108711 A376628 A261736
KEYWORD
nonn
AUTHOR
Joerg Arndt, Jan 05 2011
STATUS
approved