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 A157754 a(1) = 0, a(n) = lcm(A051904(n), A051903(n)) for n >= 2. 4
 0, 1, 1, 2, 1, 1, 1, 3, 2, 1, 1, 2, 1, 1, 1, 4, 1, 2, 1, 2, 1, 1, 1, 3, 2, 1, 3, 2, 1, 1, 1, 5, 1, 1, 1, 2, 1, 1, 1, 3, 1, 1, 1, 2, 2, 1, 1, 4, 2, 2, 1, 2, 1, 3, 1, 3, 1, 1, 1, 2, 1, 1, 2, 6, 1, 1, 1, 2, 1, 1, 1, 6, 1, 1, 2, 2, 1, 1, 1, 4, 4, 1, 1, 2, 1, 1, 1, 3, 1, 2, 1, 2, 1, 1, 1, 5, 1, 2, 2, 2 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,4 COMMENTS a(n) for n >= 2 equals LCM of minimal and maximal exponents in prime factorization of n. a(n) for n >= 2 deviates from (A072411), first different term is a(360), a(360) = 3, A072411(360)= 6. LINKS Antti Karttunen, Table of n, a(n) for n = 1..10000 FORMULA a(1) = 0, a(p) = 1, a(pq) = 1, a(pq...z) = 1, a(p^k) = k, for p = primes (A000040), pq = product of two distinct primes (A006881), pq...z = product of k (k > 2) distinct primes p, q, ..., z (A120944), p^k = prime powers (A000961(n) for n > 1) k = natural numbers (A000027). EXAMPLE For n = 12 = 2^2 * 3^1 we have a(12) = lcm(2,1) = 2. For n = 144 = 2^4 * 3^2 we have a(144) = lcm(4,2) = 4. MATHEMATICA Table[LCM @@ {Min@ #, Max@ #} - Boole[n == 1] &@ FactorInteger[n][[All, -1]], {n, 100}] (* Michael De Vlieger, Jul 12 2017 *) CROSSREFS Cf. A000040, A003990, A006881, A120944, A000961, A000027, A072411, A051904, A051903, A158378. Sequence in context: A070014 A051903 A324912 * A072411 A290107 A212180 Adjacent sequences:  A157751 A157752 A157753 * A157755 A157756 A157757 KEYWORD nonn AUTHOR Jaroslav Krizek, Mar 05 2009 STATUS approved

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Last modified April 19 20:37 EDT 2021. Contains 343117 sequences. (Running on oeis4.)