OFFSET
0,2
COMMENTS
Equals A007318^9 * [1, 0, 9, 0, 81, 0, 729, ...]. - Gary W. Adamson, Oct 23 2008
LINKS
Paolo Xausa, Table of n, a(n) for n = 0..926
Index entries for linear recurrences with constant coefficients, signature (18,-72).
FORMULA
From Philippe Deléham, Oct 18 2008: (Start)
a(n) = 18*a(n-1) - 72*a(n-2).
a(n) = 6^n*(2^n+1)/2.
G.f.: (1-9*x)/(1-18*x+72*x^2). (End)
From R. J. Mathar, Oct 21 2008: (Start)
a(n) = (12^n + 6^n)/2.
G.f.: (1-9*x)/((1-12*x)*(1-6*x)). (End)
a(n) = 3^n*A007582(n) = (6^n+12^n)/2 = A000051(n)*A000079(n)*A000244(n)/2. - M. F. Hasler, Oct 22 2008
A007318^9 * [1, 0, 9, 0, 81, 0, 729, ...] produces this sequence. - Gary W. Adamson, Oct 23 2008
a(n) = Sum_{k=0..n} A098158(n,k)*9^k. - Philippe Deléham, Oct 23 2008
E.g.f.: exp(9*x)*cosh(3*x). - Elmo R. Oliveira, Jun 13 2026
MATHEMATICA
LinearRecurrence[{18, -72}, {1, 9}, 25] (* Paolo Xausa, May 11 2026 *)
PROG
(PARI) A143079(n)=3^n*(1+1<<n)<<(n-1) \\ M. F. Hasler, Oct 22 2008
CROSSREFS
KEYWORD
nonn,easy,changed
AUTHOR
Al Hakanson (hawkuu(AT)gmail.com), Oct 15 2008
EXTENSIONS
Extended by R. J. Mathar and M. F. Hasler, Oct 21 2008
More terms from Paolo Xausa, May 11 2026
STATUS
approved
