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 A129194 a(n) = n^2*(3/4 - (-1)^n/4). 13
 0, 1, 2, 9, 8, 25, 18, 49, 32, 81, 50, 121, 72, 169, 98, 225, 128, 289, 162, 361, 200, 441, 242, 529, 288, 625, 338, 729, 392, 841, 450, 961, 512, 1089, 578, 1225, 648, 1369, 722, 1521, 800, 1681, 882, 1849, 968, 2025, 1058, 2209, 1152, 2401, 1250, 2601, 1352 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,3 COMMENTS The numerator of the integral is 2,1,2,1,2,1....; the moments of the integral are 2/(n+1)^2. The sequence alternates between twice a square and an odd square, A001105(n) and A016754(n). Partial sums of the positive elements give the absolute values of A122576. - Omar E. Pol, Aug 22 2011 Partial sums of the positive elements give A212760. - Omar E. Pol, Dec 28 2013 Conjecture: denominator of 4/n - 2/n^2. - Wesley Ivan Hurt, Jul 11 2016 Multiplicative because both A000290 and A040001 are. - Andrew Howroyd, Jul 25 2018 REFERENCES G. Pólya and G. Szegő, Problems and Theorems in Analysis II (Springer 1924, reprinted 1976), Part Eight, Chap. 1, Sect. 7, Problem 73. LINKS Vincenzo Librandi, Table of n, a(n) for n = 0..960 John M. Campbell, An Integral Representation of Kekulé Numbers, and Double Integrals Related to Smarandache Sequences, arXiv preprint arXiv:1105.3399 [math.GM], 2011. Index entries for linear recurrences with constant coefficients, signature (0,3,0,-3,0,1). FORMULA G.f.: x*(1 + 2*x + 6*x^2 + 2*x^3 + x^4)/(1-x^2)^3; a(n+1) = denominator((1/(2*Pi))*Integral_{t=0..2*Pi} exp(i*n*t)(-((Pi-t)/i)^2)), i=sqrt(-1). a(n) = 3*a(n-2) - 3*a(n-4) + a(n-6) for n > 5. - Paul Curtz, Mar 07 2011 a(n) is the numerator of the coefficient of x^4 in the Maclaurin expansion of exp(-n*x^2). - Francesco Daddi, Aug 04 2011 O.g.f. as a Lambert series: x*Sum_{n >= 1} J_2(n)*x^n/(1 + x^n), where J_2(n) denotes the Jordan totient function A007434(n). See Pólya and Szegő. - Peter Bala, Dec 28 2013 From Ilya Gutkovskiy, Jul 11 2016: (Start) E.g.f.: x*((2*x + 1)*sinh(x) + (x + 2)*cosh(x))/2. Sum_{n>=1} 1/a(n) = 5*Pi^2/24. [corrected by Amiram Eldar, Sep 11 2022] (End) a(n) = A000290(n) / A040001(n). - Andrew Howroyd, Jul 25 2018 Sum_{n>=1} (-1)^(n+1)/a(n) = Pi^2/24 (A222171). - Amiram Eldar, Sep 11 2022 MAPLE A129194:=n->n^2*(3/4 - (-1)^n/4): seq(A129194(n), n=0..80); # Wesley Ivan Hurt, Jul 11 2016 MATHEMATICA Table[n^2*(3/4 - (-1)^n/4), {n, 0, 60}] (* Wesley Ivan Hurt, Jul 11 2016 *) PROG (Magma) [n^2*(3/4-(-1)^n/4): n in [0..50]]; // Vincenzo Librandi, Apr 26 2011 (PARI) a(n) = lcm(2, n^2)/2; \\ Andrew Howroyd, Jul 25 2018 CROSSREFS Cf. A016742, A010713, A105398, A152020, A000290, A061038, A061040, A061050. - Paul Curtz, Nov 21 2008 Cf. A040001, A129204, A222171. Sequence in context: A215025 A162954 A357993 * A300780 A272347 A214300 Adjacent sequences: A129191 A129192 A129193 * A129195 A129196 A129197 KEYWORD easy,frac,nonn,mult AUTHOR Paul Barry, Apr 02 2007 EXTENSIONS More terms from Michel Marcus, Dec 28 2013 STATUS approved

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Last modified March 28 14:02 EDT 2023. Contains 361595 sequences. (Running on oeis4.)