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A098270
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a(n) = 2^n*P_n(5), 2^n times the Legendre polynomial of order n at 5.
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6
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1, 10, 148, 2440, 42256, 752800, 13660480, 251113600, 4660568320, 87140108800, 1638884021248, 30970912737280, 587599919386624, 11185644310405120, 213540626285805568, 4086692369433395200, 78378887309200261120
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OFFSET
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0,2
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COMMENTS
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Central coefficients of (1 + 10*x + 24*x^2)^n. 2^n*LegendreP(n,k) yields the central coefficients of (1 + 2*k*x + (k^2-1)*x^2)^n, with g.f. 1/sqrt(1 - 4*k*x + 4*x^2).
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LINKS
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FORMULA
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G.f.: 1/sqrt(1-20*x+4*x^2).
a(n) = Sum_{k=0..floor(n/2)} (-1)^k*binomial(n,k)*binomial(2*(n-k), n)*5^(n-2*k).
D-finite with recurrence: n*a(n) +10*(1-2*n)*a(n-1) +4*(n-1)*a(n-2) = 0. - R. J. Mathar, Sep 26 2012
a(n) ~ sqrt(72+30*sqrt(6))*(10+4*sqrt(6))^n/(12*sqrt(Pi*n)). - Vaclav Kotesovec, Oct 14 2012
a(n) = (1/3)*Sum_{k >= n} binomial(k,n)^2*(2/3)^k.
a(n) = (4^n)*Sum_{k = 0..n} binomial(n,k)^2*(3/2)^k.
a(n) = (1/3)*(2/3)^n*hypergeometric2F1([n+1, n+1], [1], 2/3).
a(n) = (4^n)*hypergeometric2F1([-n, -n], [1], 3/2)
a(n) = [x^n] ((2*x - 2)*(3 - 2*x))^n.
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MATHEMATICA
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Table[SeriesCoefficient[1/Sqrt[1-20*x+4*x^2], {x, 0, n}], {n, 0, 20}] (* Vaclav Kotesovec, Oct 14 2012 *)
Table[2^n*LegendreP[n, 5], {n, 0, 40}] (* G. C. Greubel, May 21 2023 *)
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PROG
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(Sage)
def A098270(n): return 2^n*gen_legendre_P(n, 0, 5)
(Magma) [2^n*Evaluate(LegendrePolynomial(n), 5): n in [0..40]]; // G. C. Greubel, May 21 2023
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CROSSREFS
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Sequences of the form 2^n*LegendreP(n, 2*m+1): A000079 (m=0), A084773 (m=1), this sequence (m=2).
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KEYWORD
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easy,nonn
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AUTHOR
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STATUS
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approved
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