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A077049
Left summatory matrix, T, by antidiagonals upwards.
15
1, 1, 0, 1, 1, 0, 1, 0, 0, 0, 1, 1, 1, 0, 0, 1, 0, 0, 0, 0, 0, 1, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 1, 1, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0
OFFSET
1,1
COMMENTS
If S = (s(1), s(2), ...) is a sequence written as a column vector, then T*S is the summatory sequence of S; i.e., its n-th term is Sum_{k|n} s(k). T is the inverse of the left Moebius transformation matrix, A077050. Except for the first term in some cases, column 1 of T^(-2) is A007427, column 1 of T^(-1) is A008683, Column c of T^2 is A000005, column 1 of T^3 is A007425.
This is essentially the same as A051731, which includes only the triangle. Note that the standard in the OEIS is left to right antidiagonals, which would make this the right summatory matrix, and A077051 the left one. - Franklin T. Adams-Watters, Apr 08 2009
From Gary W. Adamson, Apr 28 2010: (Start)
As defined with antidiagonals of the array = the triangle shown in the example section. Row sums of this triangle = A032741 (with a different offset): 1, 1, 2, 1, 3, 1, 3, ...
Let the triangle = M. Then lim_{n->inf} M^n = A002033, the left-shifted vector considered as a sequence: (1, 1, 1, 2, 1, 3, 1, 4, 2, 3, 1, 8, ...). (End)
LINKS
Michael De Vlieger, Table of n, a(n) for n = 1..11325 (Rows 1 <= n <= 150).
Clark Kimberling, Matrix Transformations of Integer Sequences, J. Integer Seqs., Vol. 6, 2003.
FORMULA
T(n,k)=1 if k|n, otherwise T(n,k)=0, k >= 1, n >= 1.
From Boris Putievskiy, May 08 2013: (Start)
As table T(n,k) = floor(k/n) - floor((k-1)/n).
As linear sequence a(n) = floor(A004736(n)/A002260(n)) - floor((A004736(n)-1)/A002260(n)); a(n) = floor(j/i)-floor((j-1)/i), where i=n-t*(t+1)/2, j=(t*t+3*t+4)/2-n, t=floor((-1+sqrt(8*n-7))/2). (End)
EXAMPLE
T(4,2) = 1 since 2 divides 4. Northwest corner:
1 0 0 0 0 0
1 1 0 0 0 0
1 0 1 0 0 0
1 1 0 1 0 0
1 0 0 0 1 0
1 1 1 0 0 1
From Gary W. Adamson, Apr 28 2010: (Start)
First few rows of the triangle (when T is read by antidiagonals upwards):
1;
1, 0;
1, 1, 0;
1, 0, 0, 0;
1, 1, 1, 0, 0;
1, 0, 0, 0, 0, 0;
1, 1, 0, 1, 0, 0, 0;
1, 0, 1, 0, 0, 0, 0, 0;
1, 1, 0, 0, 1, 0, 0, 0, 0;
... (End)
MAPLE
A077049 := proc(n, k)
if modp(n, k) = 0 then
1;
else
0 ;
end if;
end proc:
for d from 2 to 10 do
for k from 1 to d-1 do
n := d-k ;
printf("%d, ", A077049(n, k)) ;
end do:
end do: # R. J. Mathar, Jul 22 2017
MATHEMATICA
With[{nn = 14}, DeleteCases[#, -1] & /@ Transpose@ Table[Take[#, nn] &@ Flatten@ Join[ConstantArray[-1, k - 1], ConstantArray[Reverse@ IntegerDigits[2^(k - 1), 2], Ceiling[(nn - k + 1)/k]]], {k, nn}]] // Flatten (* Michael De Vlieger, Jul 22 2017 *)
PROG
(PARI) nn=10; matrix(nn, nn, n, k, if (n % k, 0, 1)) \\ Michel Marcus, May 21 2015
(Python)
def T(n, k):
return 1 if n%k==0 else 0
for n in range(1, 11): print([T(n - k + 1, k) for k in range(1, n + 1)]) # Indranil Ghosh, Jul 22 2017
CROSSREFS
Cf. A051731, A077050, A077051, A077052, A000005 (row sums).
Cf. A032741, A002033. - Gary W. Adamson, Apr 28 2010
Sequence in context: A364639 A342991 A285898 * A124895 A089885 A190233
KEYWORD
nonn,tabl
AUTHOR
Clark Kimberling, Oct 22 2002
EXTENSIONS
Name edited by Petros Hadjicostas, Jul 27 2019
STATUS
approved