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0, 1, 15, 99, 435, 1485, 4257, 10725, 24453, 51480, 101530, 189618, 338130, 579462, 959310, 1540710, 2408934, 3677355, 5494401, 8051725, 11593725, 16428555, 22940775, 31605795, 43006275, 57850650, 76993956, 101461140, 132473044, 171475260, 220170060, 280551612
(list;
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refs;
listen;
history;
text;
internal format)
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OFFSET
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0,3
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REFERENCES
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A. H. Beiler, Recreations in the Theory of Numbers, Dover, N. Y., 1964, pp. 194-196.
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LINKS
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FORMULA
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a(n) = (7*n+1)*binomial(n+6, 7)/8.
G.f.: x*(1+6*x)/(1-x)^9.
E.g.f.: x*(8! +262080*x +383040*x^2 +210000*x^3 +52080*x^4 +6216*x^5 + 344*x^6 +7*x^7)*exp(x)/8!
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MAPLE
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f:=n->(7*n+8)*binomial(n+7, 7)/8; [seq(f(n), n=-1..40)]; # N. J. A. Sloane, Mar 25 2015
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MATHEMATICA
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CoefficientList[Series[x(1+6x)/(1-x)^9, {x, 0, 30}], x] (* Vincenzo Librandi, Mar 20 2015 *)
Table[(7*n+1)*Binomial[n+6, 7]/8, {n, 0, 35}] (* G. C. Greubel, Aug 29 2019 *)
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PROG
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(PARI) lista(nn) = for (n=0, nn, print1((7*n+1)*binomial(n+6, 7)/8, ", ")); \\ Michel Marcus, Mar 20 2015
(Magma) [0] cat [(7*n+8)*Binomial(n+7, 7)/8: n in [0..30]]; // Vincenzo Librandi, Mar 20 2015
(Sage) [(7*n+1)*binomial(n+6, 7)/8 for n in (0..35)] # G. C. Greubel, Aug 29 2019
(GAP) List([0..35], n-> (7*n+1)*Binomial(n+6, 7)/8); # G. C. Greubel, Aug 29 2019
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CROSSREFS
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a(n)=f(n, 6) where f is given in A034261.
Cf. A093564 ((7, 1) Pascal, column m=8).
Cf. similar sequences listed in A254142.
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KEYWORD
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easy,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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