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 A007094 Numbers in base 8. (Formerly M0498) 214
 0, 1, 2, 3, 4, 5, 6, 7, 10, 11, 12, 13, 14, 15, 16, 17, 20, 21, 22, 23, 24, 25, 26, 27, 30, 31, 32, 33, 34, 35, 36, 37, 40, 41, 42, 43, 44, 45, 46, 47, 50, 51, 52, 53, 54, 55, 56, 57, 60, 61, 62, 63, 64, 65, 66, 67, 70, 71, 72, 73, 74, 75, 76, 77, 100, 101, 102, 103, 104, 105, 106, 107, 110, 111 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,3 REFERENCES N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence). LINKS Nathaniel Johnston, Table of n, a(n) for n = 0..10000 Wikipedia, Octal R. G. Wilson, V, Letter to N. J. A. Sloane, Sep. 1992 FORMULA a(0) = 0; a(n) = 10*a(n/8) if n == 0 (mod 8); a(n) = a(n-1) + 1 otherwise. - Benoit Cloitre, Dec 22 2002 G.f.: sum(d>=0, 10^d*(x^(8^d) +2*x^(2*8^d) +3*x^(3*8^d) +4*x^(4*8^d) +5*x^(5*8^d) +6*x^(6*8^d) +7*x^(7*8^d)) * (1-x^(8^d)) / ((1-x^(8^(d+1)))*(1-x))). - Robert Israel, Aug 03 2014 MAPLE A007094 := proc(n) local l: if(n=0)then return 0: fi: l:=convert(n, base, 8): return op(convert(l, base, 10, 10^nops(l))): end: seq(A007094(n), n=0..66); # Nathaniel Johnston, May 06 2011 MATHEMATICA Table[FromDigits[IntegerDigits[n, 8]], {n, 0, 70}] PROG (PARI) a(n)=if(n<1, 0, if(n%8, a(n-1)+1, 10*a(n/8))) (PARI) apply( A007094(n)=fromdigits(digits(n, 8)), [0..77]) \\ M. F. Hasler, Nov 18 2019 (Haskell) a007094 0 = 0 a007094 n = 10 * a007094 n' + m where (n', m) = divMod n 8 -- Reinhard Zumkeller, Aug 29 2013 (Python) def a(n): return int(oct(n)[2:]) print([a(n) for n in range(74)]) # Michael S. Branicky, Jun 28 2021 CROSSREFS Cf. A057104; A000042 (base 1), A007088 (base 2), A007089 (base 3), A007090 (base 4), A007091 (base 5), A007092 (base 6), A007093 (base 7), A007095 (base 9). Sequence in context: A039207 A272576 A039155 * A000433 A031492 A035060 Adjacent sequences:  A007091 A007092 A007093 * A007095 A007096 A007097 KEYWORD nonn,easy,base AUTHOR STATUS approved

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Last modified September 20 14:44 EDT 2021. Contains 347586 sequences. (Running on oeis4.)