OFFSET
1,1
COMMENTS
Also numbers k with abundance tau(phi(k)).
LINKS
Aloe Poliszuk, Table of n, a(n) for n = 1..10000
EXAMPLE
k=56 has sigma(56) = 120, tau(phi(56)) = 8, 2*56 + 8 = 120.
MATHEMATICA
q[k_] := DivisorSigma[1, k] == 2*k + DivisorSigma[0, EulerPhi[k]]; Select[Range[6500], q] (* Amiram Eldar, Jan 28 2026 *)
PROG
(PARI) isok(n) = my(f=factorint(n)); sigma(f) == 2*n + numdiv(eulerphi(f));
CROSSREFS
If we generalize to numbers x with abundance c*tau(phi(x)), then a(n) is the case of c=1, and we have:
KEYWORD
nonn
AUTHOR
Aloe Poliszuk, Jan 27 2026
STATUS
approved
