OFFSET
1,1
COMMENTS
Also numbers k with abundance -2 * tau(phi(k)).
EXAMPLE
k=13 has sigma(13) = 14, tau(phi(13)) = 6, 2*13 - 2*6 = 14.
MATHEMATICA
q[k_] := DivisorSigma[1, k] == 2*k - 2*DivisorSigma[0, EulerPhi[k]]; Select[Range[600000], q] (* Amiram Eldar, Jan 28 2026 *)
PROG
(PARI) isok(n) = my(f=factorint(n)); sigma(f) == 2*(n - numdiv(eulerphi(f)));
CROSSREFS
If we generalize to numbers x with abundance c*tau(phi(x)), then a(n) is the case of c=-2, and we have:
KEYWORD
nonn,hard,more
AUTHOR
Aloe Poliszuk, Jan 27 2026
STATUS
approved
