OFFSET
1,2
COMMENTS
Also numbers k with abundance -tau(phi(k)).
EXAMPLE
k=14 has sigma(14) = 24, tau(phi(14)) = 4, 2*14 - 4 = 24.
k=184 has sigma(184) = 360, tau(phi(184)) = 8, 2*184 - 8 = 360.
MATHEMATICA
q[k_] := DivisorSigma[1, k] == 2*k - DivisorSigma[0, EulerPhi[k]]; Select[Range[500000], q] (* Amiram Eldar, Jan 28 2026 *)
PROG
(PARI) isok(n) = my(f=factorint(n)); sigma(f) == 2*n - numdiv(eulerphi(f));
CROSSREFS
If we generalize to numbers x with abundance c*tau(phi(x)), then a(n) is the case of c=-1, and we have:
KEYWORD
nonn,hard,more
AUTHOR
Aloe Poliszuk, Jan 27 2026
STATUS
approved
