OFFSET
1,2
COMMENTS
The even-indexed Jacobsthal numbers A001045(2*n) = A002450(n) = (4^n-1)/3, for n >= 1, are terms since their representation is 2*n-1 1's.
A001045(2*n+1) - 1 = A020988(n) = (2/3)*(4^n-1) is a term for n >= 1, since its representation is 2*n 1's.
A001045(n) + 1 = A128209(n) is a term for n >= 0, since its representation for n = 0 is 1 and its representation for n >= 1 is n-1 0's between 2 1's.
A160156(n) is a term for n >= 0 since its representation is n 0's interleaved with n+1 1's.
LINKS
Amiram Eldar, Table of n, a(n) for n = 1..10000
EXAMPLE
The first 10 terms are:
n a(n) A280049(a(n))
-- ---- -------------
1 1 1
2 2 11
3 4 101
4 5 111
5 6 1001
6 10 1111
7 12 10001
8 15 10101
9 18 11011
10 21 11111
MATHEMATICA
Position[Select[Range[1000], EvenQ[IntegerExponent[#, 2]] &], _?(PalindromeQ[IntegerDigits[#, 2]] &)] // Flatten
PROG
(PARI) s(n) = if(n < 2, n > 0, n = s(n-1); until(valuation(n, 2)%2 == 0, n++); n); \\ A003159
is(n) = {my(d = binary(s(n))); d == Vecrev(d); }
CROSSREFS
KEYWORD
nonn,base,easy
AUTHOR
Amiram Eldar, Jul 14 2023
STATUS
approved
