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A363378
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Third Lie-Betti number of a cycle graph on n vertices.
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1
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12, 25, 41, 68, 105, 152, 210, 280, 363, 460, 572, 700, 845, 1008, 1190, 1392, 1615, 1860, 2128, 2420, 2737, 3080, 3450, 3848, 4275, 4732, 5220, 5740, 6293, 6880, 7502, 8160, 8855, 9588, 10360, 11172, 12025, 12920, 13858
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OFFSET
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3,1
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COMMENTS
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LINKS
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FORMULA
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a(3) = 12, a(4) = 25, a(5) = 41, a(n) = n*(n+11)*(n-2)/6 for n >= 6.
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PROG
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(Python)
values = [12, 25, 41]
for i in range(6, n+1):
result = (i*(i+11)*(i-2))/6
values.append(result)
return values
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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