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A354408
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Triangle read by rows of generalized ménage numbers: T(n,k) is the number of permutations pi in S_n such that pi(i) != i and pi(i) != i+k (mod n) for all i; n, 1 <= k < n.
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4
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0, 1, 1, 2, 4, 2, 13, 13, 13, 13, 80, 82, 80, 82, 80, 579, 579, 579, 579, 579, 579, 4738, 4740, 4738, 4752, 4738, 4740, 4738, 43387, 43387, 43390, 43387, 43387, 43390, 43387, 43387, 439792, 439794, 439792, 439794, 440192, 439794, 439792, 439794, 439792
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OFFSET
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2,4
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COMMENTS
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Conjectures: (Start)
T(n,1) <= T(n,k) for all 1 < k < n.
With the exception of T(6,3) = 80, T(n,k) > T(n,1) whenever gcd(n,k) > 1. (End)
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LINKS
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FORMULA
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T(n,k) = T(n,n-k).
T(n,k) = A000179(n) if k is coprime to n.
Conjecture: T(n,j) < T(n,k) if gcd(n,j) < gcd(n,k) and (n,k) != (6,3). - Pontus von Brömssen, May 31 2022
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EXAMPLE
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Triangle begins:
n\k| 1 2 3 4 5 6 7 8
-----+------------------------------------------------
2 | 0
3 | 1 1
4 | 2 4 2
5 | 13 13 13 13
6 | 80 82 80 82 80
7 | 579 579 579 579 579 579
8 | 4738 4740 4738 4752 4738 4740 4738
9 | 43387 43387 43390 43387 43387 43390 43387 43387
...
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PROG
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(Python)
from sympy import Matrix
return Matrix(n, n, lambda i, j:int(i!=j and i!=(j+k)%n)).per() # Pontus von Brömssen, May 31 2022
(Python)
# This version, based on the formula in A277256, is much faster than the version using permanents, at least for large n.
from sympy import factorial, gcd, sqrt
from sympy.abc import z
k=gcd(n, k)
F=((1-sqrt(1+4*z))/2)**(2*(n//k))+((1+sqrt(1+4*z))/2)**(2*(n//k))
p=(F**k).series(z, 0, n+1)
return sum((-1)**j*factorial(n-j)*p.coeff(z, j) for j in range(n+1)) # Pontus von Brömssen, Jun 02 2022
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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