login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

A353047
Number of length n words on alphabet {0,1,2} that contain each of the subwords 01, 02, 10, 12, 20, and 21 as (not necessarily contiguous) subwords.
1
12, 108, 600, 2664, 10404, 37476, 127920, 420768, 1348476, 4242204, 13169160, 40490712, 123635028, 375623892, 1137095520, 3433306896, 10347106860, 31141984140, 93639862200, 281372571720, 845074016772, 2537235316548, 7615933808400, 22856659795584, 68588501433564
OFFSET
5,1
COMMENTS
Let A be an alphabet containing m letters. Let S be the set of m^2-m ordered two-tuples of distinct letters in A. The generating function for the number of length n words on A that contain each two-tuple in S as a (not necessarily contiguous) subword is m*(m-1)!^2*x^(2*m-1)/((1-m*x)*Product_{k=1..m-1} (1-k*x)^2).
Appears to equal 12 times A222993, except that sequence only has a conjectured formula. - N. J. A. Sloane, Jun 17 2022
FORMULA
G.f.: (12*x^5)/((1 - 2*x)^2*(1 - x)^2*(1 - 3*x)).
EXAMPLE
a(5) = 12 because we have: {0, 1, 2, 0, 1}, {0, 1, 2, 1, 0}, {0, 2, 1, 0, 2}, {0, 2, 1, 2, 0}, {1, 0, 2, 0, 1}, {1, 0, 2, 1, 0}, {1, 2, 0, 1, 2}, {1, 2, 0, 2, 1}, {2, 0, 1, 0, 2}, {2, 0, 1, 2, 0}, {2, 1, 0, 1, 2}, {2, 1, 0, 2, 1}.
MATHEMATICA
nn = 15; vertices = Level[Outer[ List, {a, b, c}, {d, e, f}, {h, i, j}, {k, l, m}, {n, o, p}, {q, r, s}], {6}]; x = {a -> b, d -> e, i -> j, o -> p}; y = {b -> c, h -> i, k -> l, r -> s}; z = {e -> f, l -> m, n -> o, q -> r}; replacementlist = Table[vertices[[kk]] -> kk, {kk, 1, 729}]; G= Normal[SparseArray[Flatten[Table[Normal[Merge[ Map[{mm, vertices[[mm]] /. # /. replacementlist} -> 1 &, {x, y, z}], Total]], {mm, 1, 729}]]]]; Iwg =
Inverse[IdentityMatrix[729] - w G]; CoefficientList[ Series[Iwg[[1, 729]], {w, 0, nn}], w]
CROSSREFS
Cf. A058809, A222993, A005803 (binary words).
Sequence in context: A154671 A321672 A241230 * A037972 A111990 A053469
KEYWORD
nonn,easy
AUTHOR
Geoffrey Critzer, Apr 19 2022
STATUS
approved