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 A293928 Totients having one or more solutions to phi(m)^(k+1) = phi(phi(m)^k*m), k >= 1, m >= 1. 1
 1, 2, 4, 6, 8, 12, 16, 18, 20, 24, 32, 36, 40, 48, 54, 64, 72, 80, 84, 96, 100, 108, 120, 128, 144, 160, 162, 168, 192, 200, 216, 240, 252, 256, 272, 288, 312, 320, 324, 336, 360, 384, 400, 432, 440, 480, 486, 500, 504, 512, 544, 576, 588, 600, 624, 640, 648, 672, 684 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS "Totients" are terms of A000010. - N. J. A. Sloane, Oct 22 2017 The smallest totient absent from the list is 10. This is because the totient inverses of 10, 11 and 22 are not solutions of phi(m)^(k+1) = phi(phi(m)^k*m), k >= 1, m >= 1. The formula is recursive. For example, taking a(22) we get the following: 11664 = phi(108*324), 1259712 = phi(11664*324), 136048896 = phi(1259712*324), ... If a solution exists then the smallest value of k must be 1. This follows from a|b implies phi(a)|phi(b), and for k >= 1 a^(k-1)|a^k. Where (if ever) does this first differ from A068997? - R. J. Mathar, Oct 30 2017 LINKS Max Alekseyev, PARI scripts for various problems FORMULA 0 < phi(m)^(k+1) = phi(phi(m)^k*m), k >= 1, m >= 1. EXAMPLE 96 is a term since 96^2 = phi(96*288), with k=1 and m=288 where phi(288) = 96. PROG (PARI) isok(n) = {my(iv = invphi(n)); if (#iv, for (m = 1, #iv, if (n^2 == eulerphi(n*iv[m]), return (1)); ); ); return (0); } \\ using the invphi script by Max Alekseyev; Michel Marcus, Nov 01 2017 CROSSREFS Cf. A000010, A006511, A032447, A007366. Subsequence of A002202. Sequence in context: A320580 A325763 A068997 * A067712 A060765 A140110 Adjacent sequences:  A293925 A293926 A293927 * A293929 A293930 A293931 KEYWORD nonn AUTHOR Torlach Rush, Oct 19 2017 EXTENSIONS More terms from Michel Marcus, Oct 24 2017 STATUS approved

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Last modified July 26 09:58 EDT 2021. Contains 346294 sequences. (Running on oeis4.)