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 A289006 Conversion to octal of the binary expansion given by the first n terms of the period-3 sequence A011655 (repeat 0, 1, 1). 2
 0, 1, 3, 6, 15, 33, 66, 155, 333, 666, 1555, 3333, 6666, 15555, 33333, 66666, 155555, 333333, 666666, 1555555, 3333333, 6666666, 15555555, 33333333, 66666666, 155555555, 333333333, 666666666, 1555555555, 3333333333, 6666666666, 15555555555, 33333333333, 66666666666, 155555555555, 333333333333, 666666666666 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,3 COMMENTS The length of the n-th term is floor((n+1)/3) digits, for all n>1. [Corrected by M. F. Hasler, Jun 23 2017] LINKS Index entries for linear recurrences with constant coefficients, signature (0, 0, 11, 0, 0, -10). FORMULA a(3n) = floor(10^n/3) (= n times the digit '3'), a(3n+1) = floor(10^n/3)*2 (= n times the digit '6'), a(3n+2) = floor(10^(n+1)/6) - floor(10^n/9) (= digit '1' followed by n digits '5'). - M. F. Hasler, Jun 23 2017 G.f.: x^2*(1+x)*(4*x^2+2*x+1) / ( (x-1)*(1+x+x^2)*(10*x^3-1) ). - R. J. Mathar, Jun 29 2017 PROG (PARI) { my(x='x+O('x^33)); concat([0], Vec( x*(1+x)*(1+2*x+4*x^2)/((1-x)*(1+x+x^2)*(1-10*x^3)) )) } \\ Joerg Arndt, Jun 21 2017 (PARI) A289006(n)=if(n%3==2, 10^(n\3+1)\6-10^(n\3)\9, 10^(n\3)\3<<(n%3)) \\ M. F. Hasler, Jun 23 2017 CROSSREFS A033129(n-1) written in base 8. Cf. A011655. Trisections: A099915, A002277, A002280. Sequence in context: A305839 A322110 A232973 * A152167 A105476 A000599 Adjacent sequences:  A289003 A289004 A289005 * A289007 A289008 A289009 KEYWORD nonn,base,easy AUTHOR Peter Schonefeld, Jun 21 2017 STATUS approved

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Last modified December 12 12:50 EST 2019. Contains 329958 sequences. (Running on oeis4.)