OFFSET
0,2
COMMENTS
Number of ways to write n as an ordered sum of 12 squares of triangular numbers (A000537).
Every number is the sum of three triangular numbers (Fermat's polygonal number theorem).
Conjecture: a(n) > 0 for all n.
Extended conjecture: every number is the sum of at most 12 squares of triangular numbers (or partial sums of cubes).
Is there a solution, in analogy with Waring's problem (see A002804), for the partial sums of k-th powers?
LINKS
FORMULA
G.f.: (Sum_{k>=0} x^(k^2*(k+1)^2/4))^12.
MATHEMATICA
nmax = 50; CoefficientList[Series[Sum[x^(k^2 (k + 1)^2/4), {k, 0, nmax}]^12, {x, 0, nmax}], x]
CROSSREFS
KEYWORD
nonn
AUTHOR
Ilya Gutkovskiy, May 06 2017
STATUS
approved