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A260374
The distance between n! and the nearest perfect square.
2
0, 0, 1, 2, 1, 1, 9, 1, 81, 476, 225, 324, 4604, 74879, 176400, 215296, 3444736, 11551671, 45680444, 255004929, 1158920361, 2657058876, 24923993276, 130518272975, 97216010329, 2430400258225, 1553580508516, 4666092737476, 538347188396016, 2137864362693921
OFFSET
0,4
FORMULA
a(n) = abs(n!-A260373(n)).
EXAMPLE
6!=720. The nearest perfect square is 729. The difference between these is 9, so a(6)=9.
PROG
(PARI) a(n)=abs(n!-round(sqrt(n!))^2) \\ Charles R Greathouse IV, Jul 23 2015
(Python)
from gmpy2 import isqrt
A260374_list, g = [0], 1
for i in range(1, 1001):
g *= i
s = isqrt(g)
t = g-s**2
A260374_list.append(int(t if t-s <= 0 else 2*s+1-t)) # Chai Wah Wu, Jul 23 2015
CROSSREFS
Sequence in context: A087127 A144946 A332717 * A157109 A185814 A174553
KEYWORD
nonn
STATUS
approved