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A252115
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Numbers n such that the sum of the heptagonal numbers H(n), H(n+1) and H(n+2) is equal to the pentagonal number P(m) for some m.
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2
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573, 26951, 59482389, 2794406159, 6167253128301, 289729619423063, 639433138789094469, 30039746398227684383, 66297706689763639679133, 3114580985771313152847719, 6873878824368640550422845813, 322925985736701543915329589551, 712697504201891682859177859976909
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OFFSET
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1,1
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COMMENTS
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Also nonnegative integers x in the solutions to 15*x^2-3*y^2+21*x+y+16 = 0, the corresponding values of y being A252116.
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LINKS
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FORMULA
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G.f.: x*(x^4+26*x^3-45652*x^2-26378*x-573) / ((x-1)*(x^2-322*x+1)*(x^2+322*x+1)).
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EXAMPLE
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573 is in the sequence because H(573)+H(574)+H(575) = 819963+822829+825700 = 2468492 = P(1283).
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MATHEMATICA
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LinearRecurrence[{1, 103682, -103682, -1, 1}, {573, 26951, 59482389, 2794406159, 6167253128301}, 20] (* Harvey P. Dale, Jul 21 2023 *)
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PROG
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(PARI) Vec(x*(x^4+26*x^3-45652*x^2-26378*x-573)/((x-1)*(x^2-322*x+1)*(x^2+322*x+1)) + O(x^100))
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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