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A252114
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T(n,k)=Number of (n+2)X(k+2) 0..3 arrays with every 3X3 subblock row and column sum equal to 0 2 3 6 or 7 and every 3X3 diagonal and antidiagonal sum not equal to 0 2 3 6 or 7
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9
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1417, 1929, 1929, 1568, 1424, 1568, 1600, 724, 724, 1600, 1884, 584, 554, 584, 1884, 2058, 624, 776, 776, 624, 2058, 2468, 788, 1258, 1314, 1258, 788, 2468, 3149, 1180, 1634, 1956, 1956, 1634, 1180, 3149, 3950, 1668, 2476, 2658, 3528, 2658, 2476, 1668
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OFFSET
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1,1
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COMMENTS
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Table starts
.1417.1929.1568..1600..1884...2058...2468....3149....3950....5208.....6792
.1929.1424..724...584...624....788...1180....1668....2472....3888.....5640
.1568..724..554...776..1258...1634...2476....3938....5956....9176....14532
.1600..584..776..1314..1956...2658...4488....7248...10632...17952....28992
.1884..624.1258..1956..3528...6070..11760...21344...39200...80832...147840
.2058..788.1634..2658..6070...9834..17772...38610...70968..132528...284488
.2468.1180.2476..4488.11760..17772..33216...84864..142176..265728...678912
.3149.1668.3938..7248.21344..38610..84864..252160..478368.1145856..3467264
.3950.2472.5956.10632.39200..70968.142176..478368.1017408.2120448..6956288
.5208.3888.9176.17952.80832.132528.265728.1145856.2120448.4251648.18333696
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LINKS
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FORMULA
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Empirical for column k:
k=1: [linear recurrence of order 25] for n>33
k=2: a(n) = 6*a(n-3) -8*a(n-6) for n>13
k=3: a(n) = 6*a(n-3) -8*a(n-6) for n>11
k=4: a(n) = 4*a(n-3) for n>8
k=5: a(n) = 12*a(n-3) -32*a(n-6) for n>11
k=6: a(n) = 12*a(n-3) -32*a(n-6) for n>11
k=7: a(n) = 8*a(n-3) for n>8
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EXAMPLE
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Some solutions for n=4 k=4
..3..0..0..3..0..0....3..0..0..3..0..0....2..0..0..3..0..0....0..3..3..0..3..3
..0..1..1..0..1..1....0..1..1..0..1..1....0..1..1..0..1..1....3..2..2..3..2..2
..0..1..1..0..1..1....0..1..1..0..1..1....0..1..1..0..1..1....3..2..2..3..2..2
..3..0..0..2..0..0....3..0..0..2..0..0....2..0..0..2..0..0....1..3..3..1..3..3
..0..1..1..0..1..1....0..1..1..0..1..1....0..1..1..0..1..1....3..2..2..3..2..2
..0..2..1..0..1..1....0..2..1..0..1..2....0..1..1..0..1..1....3..1..2..3..2..2
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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