login
A249677
Triangle, read by rows, with row n forming the coefficients in Product_{k=0..n} (1 + k^3*x).
9
1, 1, 1, 1, 9, 8, 1, 36, 251, 216, 1, 100, 2555, 16280, 13824, 1, 225, 15055, 335655, 2048824, 1728000, 1, 441, 63655, 3587535, 74550304, 444273984, 373248000, 1, 784, 214918, 25421200, 1305074809, 26015028256, 152759224512, 128024064000, 1, 1296, 616326, 135459216, 14320729209, 694213330464, 13472453691584, 78340747014144, 65548320768000
OFFSET
0,5
COMMENTS
Column 1 forms the squares of the triangular numbers (A000537).
Main diagonal forms the cubes of the factorial numbers (A000442).
Row sums equal Product_{k=1..n} (k^3 + 1) = n!*Product_{k=1..n} (k*(k-1) + 1) = n!*A130032(n).
LINKS
FORMULA
From Seiichi Manyama, May 09 2026: (Start)
T(n,k) = T(n-1,k) + n^3 * T(n-1,k-1).
T(n,k) = Sum_{1 <= x_1 < x_2 < ... < x_{n-k} <= n} ( n!/Product_{j=1..n-k} x_j )^3.
T(n,k) = Sum_{1 <= x_1 < x_2 < ... < x_k <= n} ( Product_{j=1..k} x_j )^3. (End)
EXAMPLE
Triangle begins:
1;
1, 1;
1, 9, 8;
1, 36, 251, 216;
1, 100, 2555, 16280, 13824;
1, 225, 15055, 335655, 2048824, 1728000;
1, 441, 63655, 3587535, 74550304, 444273984, 373248000;
1, 784, 214918, 25421200, 1305074809, 26015028256, 152759224512, 128024064000;
...
PROG
(PARI) {T(n, k)=polcoeff(prod(m=0, n, 1 + m^3*x +x*O(x^n)), k)}
for(n=0, 10, for(k=0, n, print1(T(n, k), ", ")); print(""))
CROSSREFS
Columns k=0..3 give A000012, A000537, A347107, A352980.
Diagonals give A000442, A066989, A394716, A394861.
Row sums give A255433.
Sequence in context: A185260 A275615 A385962 * A094135 A021897 A378205
KEYWORD
nonn,tabl
AUTHOR
Paul D. Hanna, Nov 03 2014
STATUS
approved