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A243759 Triangle T(m,k): exponent of the highest power of 3 dividing the binomial coefficient binomial(m,k). 3
0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 1, 1, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 2, 2, 1, 2, 2, 1, 2, 2, 0, 0, 0, 2, 1, 1, 2, 1, 1, 2, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 0, 0, 0, 0, 1, 1, 0, 2, 2, 1, 2, 2 (list; table; graph; refs; listen; history; text; internal format)
OFFSET
0,47
COMMENTS
T(m,k) is the number of 'carries' that occur when adding k and n-k in base 3 using the traditional addition algorithm.
LINKS
Tyler Ball, Tom Edgar, and Daniel Juda, Dominance Orders, Generalized Binomial Coefficients, and Kummer's Theorem, Mathematics Magazine, Vol. 87, No. 2, April 2014, pp. 135-143.
FORMULA
T(m,k) = log_3(A242849(m,k)).
From Antti Karttunen, Oct 28 2014: (Start)
a(n) = A007949(A007318(n)).
a(n) * A083093(n) = 0 and a(n) + A083093(n) > 0 for all n.
(End)
EXAMPLE
The triangle begins:
0,
0, 0,
0, 0, 0,
0, 1, 1, 0;
0, 0, 1, 0, 0;
0, 0, 0, 0, 0, 0;
0, 1, 1, 0, 1, 1, 0;
0, 0, 1, 0, 0, 1, 0, 0;
0, 0, 0, 0, 0, 0, 0, 0, 0;
0, 2, 2, 1, 2, 2, 1, 2, 2, 0;
MAPLE
A243759:= (m, k) -> padic[ordp](binomial(m, k), 3);
for m from 0 to 50 do
seq(A243759(m, k), k=0..m)
od; # Robert Israel, Jun 15 2014
MATHEMATICA
T[m_, k_] := IntegerExponent[Binomial[m, k], 3];
Table[T[m, k], {m, 0, 12}, {k, 0, m}] // Flatten (* Jean-François Alcover, Jun 05 2022 *)
PROG
(Sage)
m=50
T=[0]+[3^valuation(i, 3) for i in [1..m]]
Table=[[prod(T[1:i+1])/(prod(T[1:j+1])*prod(T[1:i-j+1])) for j in [0..i]] for i in [0..m-1]]
[log(Integer(x), base=3) for sublist in Table for x in sublist]
(Scheme) (define (A243759 n) (A007949 (A007318 n))) ;; Antti Karttunen, Oct 28 2014
CROSSREFS
Row sums: A249343.
Sequence in context: A365096 A102297 A269570 * A098398 A306211 A131714
KEYWORD
nonn,tabl
AUTHOR
Tom Edgar, Jun 10 2014
EXTENSIONS
Name clarified by Antti Karttunen, Oct 28 2014
STATUS
approved

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Last modified April 24 04:14 EDT 2024. Contains 371918 sequences. (Running on oeis4.)