OFFSET
0,2
FORMULA
a(n) = [x^(n^3)] (1/(1 - x))*(Sum_{k>=0} x^(k^3))^2. - Ilya Gutkovskiy, Apr 20 2018
PROG
(Python)
for a in range(99):
n = a*a*a
k = 0
for x in range(99):
s = x*x*x
if s>n: break
for y in range(99):
sy = s + y*y*y
if sy>n: break
k+=1
print(str(k), end=', ')
(PARI) a(n) = n++; p = Pol((1/(1 - x))*sum(k=0, n, x^(k^3))^2 + O(x^(n^3))); polcoeff(p, (n-1)^3); \\ Michel Marcus, Apr 21 2018
CROSSREFS
KEYWORD
nonn
AUTHOR
Alex Ratushnyak, Apr 01 2013
STATUS
approved