OFFSET
1,1
COMMENTS
If we change the three initial terms of A214551 (as in A214331 and A214626), again read the sequence mod 2, and decompose the result into strings 0111010(01)^n, will the sequence of values of n have anything in common with the current sequence? Is A214809 in any way characteristic of this family of sequences?
LINKS
N. J. A. Sloane, Table of n, a(n) for n = 1..916
N. J. A. Sloane, State diagram [State diagram for A214551 mod 2 for any three initial terms. Nodes are labeled with a(n-2) a(n-1) a(n), edges are labeled with a(n+1).]
EXAMPLE
Let s = 0111010. Then 0, A214330 starts
s1010s10ss10101010ss101010sss10s10s101010s10s101010101010s10101010ssss101\
01010s1010ss10s1010s10101010s1010s10s10sss10101010101010sss101010ss10ss10\
10101010101010s10s1010101010sss101010s10ss10sss10s10s10101010sss10s10ssss\
s101010s10s10s1010ss1010s1010ss10s1010101010s10s101010s1010sss10101010sss\
..., in which the successive numbers of 10's are 2, 1, 0, 4, 0, 3, 0, 0, ...
PROG
(Shell) # Using b-file for A214330, condense 10000 terms into one long string; prefix with 0.
# Using vi, s/0111010/s/g; then s/10/a/g;
# Using tr, break up so that there is one s per line.
# Using awk, count the a's per line.
CROSSREFS
KEYWORD
nonn
AUTHOR
N. J. A. Sloane, Jul 30 2012
STATUS
approved