OFFSET
1,6
COMMENTS
Coefficient of x^(n-1): A000045(n) (Fibonacci numbers).
n-th row sum: 2^(n-1).
Mirror image of triangle in A053538. - Philippe Deléham, Mar 05 2012
Subtriangle of the triangle T(n,k) given by (1, 0, -1, 1, 0, 0, 0, 0, 0, 0, 0, ...) DELTA (0, 1, 1, -1, 0, 0, 0, 0, 0, 0, 0, ...) where DELTA is the operator defined in A084938. - Philippe Deléham, Mar 12 2012
FORMULA
u(n,x) = u(n-1,x) + x*v(n-1,x),
v(n,x) = x*u(n-1,x) + x*v(n-1,x),
where u(1,x) = 1, v(1,x) = 1.
T(n,k) = A208747(n,k)/2^k. - Philippe Deléham, Mar 05 2012
From Philippe Deléham, Mar 12 2012: (Start)
As DELTA-triangle T(n,k) with 0<=k<=n:
G.f.: (1-y*x+y*x^2-y^2*x^2)/(1-x-y*x+t*x^2-y^2*x^2).
T(n,k) = T(n-1,k) + T(n-1,k-1) - T(n-2,k-1) + T(n-2,k-2), T(0,0) = T(1,0) = T(2,0) = T(2,1) = 1, T(1,1) = T(2,2) = 0 and T(n,k) = 0 if k<0 or if k>n. (End)
O.g.f.: 1/(1 - z - x*z(1 - z + x*z)) = 1 + (1 + x)*z + (1 + x + 2*x^2)*z^2 + (1 + x + 3*x + 3*x^2)*z^3 + .... - Peter Bala, Dec 31 2015
u(n,x) = Sum_{j=1..floor((n+1)/2)} (-1)^(j-1)*binomial(n-j,j-1)*(x*(1-x))^(j-1)* (1+x)^(n+1-2*j) for n>=1. - Werner Schulte, Mar 07 2017
T(n,k) = Sum_{j=0..floor((k-1)/2)} binomial(k-1-j,j)*binomial(n-k+j,j) for k,n>0 and k<=n (conjectured). - Werner Schulte, Mar 07 2017
EXAMPLE
First five rows:
1
1, 1
1, 1, 2
1, 1, 3, 3
1, 1, 4, 5, 5
First five polynomials u(n,x): 1, 1 + x, 1 + x + x^2, 1 + x + 3*x^2 + 3*x^3, 1 + x + 4*x^2 + 5*x^3 + 5*x^4.
(1, 0, -1, 1, 0, 0, ...) DELTA (0, 1, 1, -1, 0, 0, ...) begins:
1
1, 0
1, 1, 0
1, 1, 2, 0
1, 1, 3, 3, 0
1, 1, 4, 5, 5, 0
1, 1, 5, 7, 10, 8, 0
1, 1, 6, 9, 16, 18, 13, 0
1, 1, 7, 11, 23, 31, 33, 21, 0
MATHEMATICA
u[1, x_] := 1; v[1, x_] := 1; z = 13;
u[n_, x_] := u[n - 1, x] + x*v[n - 1, x];
v[n_, x_] := x*u[n - 1, x] + x*v[n - 1, x];
Table[Expand[u[n, x]], {n, 1, z/2}]
Table[Expand[v[n, x]], {n, 1, z/2}]
cu = Table[CoefficientList[u[n, x], x], {n, 1, z}];
TableForm[cu]
Flatten[%] (* A208342 *)
Table[Expand[v[n, x]], {n, 1, z}]
cv = Table[CoefficientList[v[n, x], x], {n, 1, z}];
TableForm[cv]
Flatten[%] (* A208343 *)
CROSSREFS
KEYWORD
AUTHOR
Clark Kimberling, Feb 25 2012
STATUS
approved