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A190704
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[(bn+c)r]-b[nr]-[cr], where (r,b,c)=(sqrt(3),4,2) and [ ]=floor.
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5
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3, 2, 1, 4, 3, 2, 0, 3, 2, 1, 0, 3, 2, 1, 4, 3, 2, 1, 4, 3, 1, 0, 3, 2, 1, 0, 3, 2, 1, 4, 3, 2, 1, 4, 2, 1, 0, 3, 2, 1, 0, 3, 2, 1, 4, 3, 2, 1, 3, 2, 1, 0, 3, 2, 1, 4, 3, 2, 1, 4, 3, 2, 0, 3, 2, 1, 0, 3, 2, 1, 4, 3, 2, 1, 4, 3, 1, 0, 3, 2, 1, 0, 3, 2, 1, 4, 3, 2, 1, 4, 2, 1, 0, 3, 2, 1, 0, 3, 2, 1, 4, 3, 2, 0, 3, 2, 1, 0, 3, 2, 1, 4, 3, 2, 1, 4, 3, 1, 0, 3, 2, 1, 0, 3, 2, 1, 4, 3, 2, 1, 4, 2
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OFFSET
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1,1
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COMMENTS
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Write a(n)=[(bn+c)r]-b[nr]-[cr]. If r>0 and b and c are integers satisfying b>=2 and 0<=c<=b-1, then 0<=a(n)<=b. The positions of 0 in the sequence a are of interest, as are the position sequences for 1,2,...,b. These b+1 position sequences comprise a partition of the positive integers.
Examples:
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LINKS
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MATHEMATICA
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r = Sqrt[3]; b = 4; c = 2;
f[n_] := Floor[(b*n + c)*r] - b*Floor[n*r] - Floor[c*r];
t = Table[f[n], {n, 1, 200}] (* A190704 *)
Flatten[Position[t, 0]] (* A190673 *)
Flatten[Position[t, 1]] (* A190706 *)
Flatten[Position[t, 2]] (* A190707 *)
Flatten[Position[t, 3]] (* A190708 *)
Flatten[Position[t, 4]] (* A190709 *)
With[{r=Sqrt[3], nn=140}, Table[Floor[(4n+2)r]-4Floor[n r]-Floor[2r], {n, nn}]] (* Harvey P. Dale, Mar 18 2023 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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