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A190487
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a(n) = [(bn+c)r]-b[nr]-[cr], where (r,b,c)=(sqrt(2),3,0) and []=floor.
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25
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1, 2, 0, 1, 0, 1, 2, 0, 2, 0, 1, 2, 1, 2, 0, 1, 0, 1, 2, 0, 2, 0, 1, 2, 1, 2, 0, 1, 0, 1, 2, 0, 2, 0, 1, 2, 0, 2, 0, 1, 2, 1, 2, 0, 1, 0, 1, 2, 0, 2, 0, 1, 2, 1, 2, 0, 1, 0, 1, 2, 0, 2, 0, 1, 2, 1, 2, 0, 1, 2, 1, 2, 0, 1, 0, 1, 2, 0, 2, 0, 1, 2, 1, 2, 0, 1, 0, 1, 2, 0, 2, 0, 1, 2, 1, 2, 0, 1, 0, 1, 2, 0, 1, 0, 1, 2, 0, 2, 0, 1, 2, 1, 2, 0, 1, 0, 1, 2, 0, 2, 0, 1, 2, 1, 2, 0, 1, 0, 1, 2, 0, 2, 0, 1, 2, 0, 2, 0
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OFFSET
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1,2
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COMMENTS
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Write a(n) = [(bn+c)r]-b[nr]-[cr]. If r>0 and b and c are integers satisfying b>=2 and 0<=c<=b-1, then 0<=a(n)<=b. The positions of 0 in the sequence a are of interest, as are the position sequences for 1,2,...,b. These b+1 position sequences comprise a partition of the positive integers.
Examples:
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LINKS
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MATHEMATICA
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r = Sqrt[2]; b = 3; c = 0;
f[n_] := Floor[(b*n + c)*r] - b*Floor[n*r] - Floor[c*r];
t = Table[f[n], {n, 1, 200}] (* A190487 *)
Flatten[Position[t, 0]] (* A190488 *)
Flatten[Position[t, 1]] (* A190489 *)
Flatten[Position[t, 2]] (* A190490 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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