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A190482 Convex, obtuse, hexagonal lattice numbers 14
7, 10, 12, 13, 14, 16, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
COMMENTS
These are the integers N for which it is possible to arrange N points in a subset of a hexagonal lattice such that:
1. The points are not all collinear.
2. The convex hull of the points consists entirely of line segments between nearest-neighbor lattice points in the set. (In other words, the natural polygon you get by following nearest-neighbor connections around the outside of the set is a convex polygon.)
3. The convex hull contains only obtuse angles, which will necessarily be 120 degrees.
These can also be thought of as "convenient bundle of cylinders" numbers, because if you are carrying a bundle of N parallel, identical cylinders, only if N is in this list can they be arranged in such a way that there are no "gaps", and also no single cylinders sticking out of the pattern creating "bulges".
The greatest integer that is absent from this list is 17. (This can be proved by exhaustion - it's possible to find infinite sequences of patterns that eventually cover every possible remainder of N mod 6, and 17 is the last N that cannot be achieved.)
LINKS
EXAMPLE
For N = 2, 3, 4, 5, or 6, it is impossible to arrange N cylinders in a neat bundle with no bulges or dents, so they are not in the list. But for N = 7, six cylinders can surround a central one, so 7 is in the list.
It's unclear whether 1 should be included, but the strict definition given above excludes N = 1.
PROG
(PARI) a(n)=if(n>6, n+11, [7, 10, 12, 13, 14, 16][n]) \\ Charles R Greathouse IV, Aug 26 2011
CROSSREFS
Sequence in context: A247868 A048792 A024585 * A128783 A024586 A050419
KEYWORD
nonn,easy
AUTHOR
Keenan Pepper, May 24 2011
STATUS
approved

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Last modified April 25 01:35 EDT 2024. Contains 371964 sequences. (Running on oeis4.)